The answer is; non-metals have a high ionization energy
This means that it would take more energy to dislodge an electron from the valence orbital than it would take to do the same to a metal atom. Therefore it would be easier to share electrons for non-metals while it would be easier to lose an electron for metals to reach a stable electron configuration.
The answer would be transducers
F = ma = m dv/dt
F dt = m dv
integrate both sides ( assuming constant force , mass) , zero inital conditions
Ft = mv
mv = P
P = Ft = 5 * 100 = 500 N.s
Answer:
At 3.86K
Explanation:
The following data are obtained from a straight line graph of C/T plotted against T2, where C is the measured heat capacity and T is the temperature:
gradient = 0.0469 mJ mol−1 K−4 vertical intercept = 0.7 mJ mol−1 K−2
Since the graph of C/T against T2 is a straight line, the are related by the straight line equation: C /T =γ+AT². Multiplying by T, we get C =γT +AT³ The electronic contribution is linear in T, so it would be given by the first term: Ce =γT. The lattice (phonon) contribution is proportional to T³, so it would be the second term: Cph =AT³. When they become equal, we can solve these 2 equations for T. This gives: T = √γ A .
We can find γ and A from the graph. Returning to the straight line equation C /T =γ+AT². we can see that γ would be the vertical intercept, and A would be the gradient. These 2 values are given. Substituting, we f ind: T =
√0.7/ 0.0469 = 3.86K.