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bearhunter [10]
3 years ago
6

An object is held at an unknown height above Earth’s surface, where the acceleration due to gravity of the object is considered

to be constant. After the object is released from rest, a student must determine the object’s speed the instant the object makes contact with the ground.
Which of the following equations could the student use to determine the object’s speed by using the fewest measuring tools if the student does not have access to a motion sensor? Select two answers.

A) vₓ =vₓ₀ +aₓ t
B) x= x₀ + vₓ₀ t + (1/2)aₓt²
C) v²x=v² x₀+2aₓ (x−x₀ )
D) v¯=(x−x₀) /t
Physics
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

Options A and B.

Explanation:

Gravitational acceleration, initial height, intial speed and time are required to determine final speed. The option D is incorrect, since speed varies in time. Option C is dimentionally wrong.

The correct strategy is calculating the initial height from option B. Later, substituting time in equation A to derive an expression of the final velocity in terms of position. Hence, the required equations are options A and B.

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Answer:

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A 48-kg woman pushes a 12-kg grocery cart with a force of 24 N. What is the magnitude of the force that the grocery cart exerts
Nata [24]

The correct answer is B. 24 N.

To figure out the exact force the cart exerts on the woman, we have to use Newton's third law of motion.  Newton's third law of motion states that every action has an equal and opposite reaction. This means that if object  1 exerts a force on object 2 , object 2 will exert an equal but opposite force on object 1.

This law allows us to ignore the masses of the chart and the women and focus on the  pairs of forces the woman and the chart apply to each other.  Since the woman exerts a force of 24 N on the chart, the chart will exert a force of 24 N on the woman.

The correct answer is B. 24 N.

4 0
3 years ago
Describe five things that you do to make yourself feel warmer or cooler.
stira [4]
Buy a fan or heater, get a blanket, take a shower, go outside, go by the fireplace
7 0
3 years ago
5. the combustion of a single molecule of methane produces about 10 ev of energy. a methane molecule has a mass of 16 amu. the f
Alchen [17]

The mass of methane will produce as much energy as a single gram of uranium-235 1,287 kilograms of methane. Option D is correct.

<h3>What is uranium?</h3>

Uranium, with the atomic number 92 and the symbol U in the periodic table, is a weakly radioactive element. One of the heavy metals that may be used as a concentrated energy source is uranium.

Given data;

⇒One mole of U-235 = 235 grams

=> 1 gram of U-235 = 1/235 moles

⇒1 mole of U-235 = 6.023 x 10²³ atoms

The no of atoms is;

=> 1/235 moles of U-235

⇒N = 6.023 x 10²³/235 atoms

⇒N=25.6 x 10²⁰ atoms

If one atom of U-235 gives is 189 x 10⁶ eV energy,25.6 x 10²⁰ atoms of U-235 gives;

=> 25.6 x 10²⁰ atoms of U-235 gives;

E = 25.6 x 10²⁰ x 189 x 10⁶

E= 4.8 x 10²⁹ eV energy

One methane molecule produces;

E = 10 eV of energy

=> To produce 4.8 x 10²⁹ eV energy, no. of molecules required;

= 4.8 x 10²⁸

6.032 x 10²³ molecules of methane = 16 gms

=> 4.8 x 10²⁸ molecules of methane = 16 x 4.8 x 10²⁸/ 6.032 x 10²³ gms

m= 12.75 x 10⁵ gms

m= 1275 kilograms of methane

m≅ 1287 kilograms of methane

1 gram of U-235 has the same amount of energy as 1287 kilograms of methane.

Hence option D is correct,

To learn more about uranium refer to the link;

brainly.com/question/9099776

#SPJ1

7 0
1 year ago
Typical Pressurized Water Reactors can produce 1100 to 1500
lozanna [386]

Answer: about 1,100,000,000 to 1,500,000,000 Joules/second

Explanation:

1 MW (megawatt) = 1,000,000.00 J/s (joules per second)

1100(1,000,000) = 1,100,000,000

1500(1,000,000) = 1,500,000,000

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2 years ago
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