1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bearhunter [10]
3 years ago
6

An object is held at an unknown height above Earth’s surface, where the acceleration due to gravity of the object is considered

to be constant. After the object is released from rest, a student must determine the object’s speed the instant the object makes contact with the ground.
Which of the following equations could the student use to determine the object’s speed by using the fewest measuring tools if the student does not have access to a motion sensor? Select two answers.

A) vₓ =vₓ₀ +aₓ t
B) x= x₀ + vₓ₀ t + (1/2)aₓt²
C) v²x=v² x₀+2aₓ (x−x₀ )
D) v¯=(x−x₀) /t
Physics
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

Options A and B.

Explanation:

Gravitational acceleration, initial height, intial speed and time are required to determine final speed. The option D is incorrect, since speed varies in time. Option C is dimentionally wrong.

The correct strategy is calculating the initial height from option B. Later, substituting time in equation A to derive an expression of the final velocity in terms of position. Hence, the required equations are options A and B.

You might be interested in
Help!! Sorry for the picture being sideways
Lorico [155]

Answer:

what?

Explanation:

4 0
3 years ago
How was the solar system formed? Please explain.
navik [9.2K]
Scientists believe that thesolar system<span> was </span>formed<span> when a cloud of gas and dust in space was disturbed, maybe by the explosion of a nearby star (called a supernova). This explosion made waves in space which squeezed the cloud of gas and dust.</span>
4 0
3 years ago
Read 2 more answers
The closest stars are 4 light years away from us. How far away must you be from a 854 kHz radio station with power 50.0 kW for t
Lubov Fominskaja [6]

Answer:

The distance from the radio station is 0.28 light years away.

Solution:

As per the question:

Distance, d = 4 ly

Frequency of the radio station, f = 854 kHz = 854\times 10^{3}\ Hz

Power, P = 50 kW = 50\times 10^{3}\ W

I_{p} = 1\ photon/s/m^{2}

Now,

From the relation:

P = nhf

where

n = no. of photons/second

h = Planck's constant

f = frequency

Now,

n = \frac{P}{hf} = \frac{50\times 10^{3}}{6.626\times 10^{- 34}\times 854\times 10^{3}} = 8.836\times 10^{31}\ photons/s

Area of the sphere, A = 4\pi r^{2}

Now,

Suppose the distance from the radio station be 'r' from where the intensity of the photon is 1\ photon/s/m^{2}

I_{p} = \frac{n}{A} = \frac{n}{4\pi r^{2}}

1 = \frac{8.836\times 10^{31}}{4\pi r^{2}}

r = \sqrt{\frac{8.836\times 10^{31}}{4\pi}} = 2.65\times 10^{15}\ m

Now,

We know that:

1 ly = 9.4607\times 10^{15}\ m

Thus

r = \frac{2.65\times 10^{15}}{9.4607\times 10^{15}} = 0.28\ ly

5 0
3 years ago
When the tympanic membrane vibrates with the same frequency as the incoming sound waves it is known asamplitude.pitch.hertz.reso
Sphinxa [80]
<h2>Answer: Resonance </h2>

Resonance is a phenomenon that occurs when a body capable of vibrating is subjected to the action of a periodic force, whose frequency of vibration approaches the characteristic frequency of vibration (called resonance frequence) of said body. This is due a relatively small force applied in a repeated form, causing the amplitude of the oscillating system to become very large.

In other words, for the specific case of sound waves, this phenomenon occurs when the frequency of the  wave that is external to the system or body coincides with the resonance frequency (characteristic frequency that reaches the maximum degree of oscillation) of this system or body.

In these circumstances the body vibrates, progressively increasing the amplitude of movement after each successive actions of the force. However, this effect can be destructive in some rigid materials.

4 0
3 years ago
A 3.0-kg brick rests on a perfectly smooth ramp inclined at 34° above the horizontal. The brick is kept from sliding down the pl
Firdavs [7]

Answer:

d=0.137 m ⇒13.7 cm

Explanation:

Given data

m (Mass)=3.0 kg

α(incline) =34°

Spring Constant (force constant)=120 N/m

d (distance)=?

Solution

F=mg

F=(3.0)(9.8)

F=29.4 N

As we also know that

Force parallel to the incline=FSinα

F=29.4×Sin(34)

F=16.44 N

d(distance)=F/Spring Constant

d(distance)=16.44/120

d(distance)=0.137 m ⇒13.7 cm

4 0
3 years ago
Other questions:
  • Nasa has developed deep-space 1 (ds-1), a spacecraft that is scheduled to rendezvous with the asteroid named 1992 kd (which orbi
    8·1 answer
  • A balloon drifts 50 m toward the east in 6 s; then the wind suddenly changes and the balloon flies 30 m toward the west in the n
    6·1 answer
  • What is wave motion​
    10·1 answer
  • If the total mass hanging on one end of the string that creates the tension in the string is 0.300 kg , what is the mass density
    10·1 answer
  • Determine the pressure point in a liquid container within a pool. The height of the liquid column is 9 m, The density of the liq
    8·1 answer
  • One astronomer has observed an apparent lengthening of the electromagnetic waves given off by a star. Which of these conclusions
    9·2 answers
  • Ayudaaa no se como resolverlo con procedimiento :(
    5·1 answer
  • Some individuals have developed to use echolocation and thus able to see even if they are blind, True or False
    5·1 answer
  • Help please
    15·1 answer
  • What is the job of the front center position? a. Set the ball b. Receive the ball c. Serve the ball
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!