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Serga [27]
3 years ago
7

maltase is an enzyme that breaks down maltose. if a maltase enzyme has just completed catalyzing the decomposition of maltose, t

hen
Chemistry
1 answer:
Softa [21]3 years ago
5 0
An ATPase enzyme breaks down ATP into ADP and phosphate using water in the reaction. This enzyme is in the enzyme class
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A 29.05 gram sample of cobalt is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 40.88 g. Determ
deff fn [24]

The empirical formula of the oxide is Co₂O₃.

<em>Step 1</em>. Calculate the <em>mass of oxygen</em>

Your reaction is

 Cobalt + oxygen ⟶ cobalt oxide

29.05 g +    x g    ⟶     40.88 g

According to the <em>Law of Conservation of Mass</em>, the total mass of the reactants must equal the total mass of the products. Thus,

29.05 g + <em>x</em> g ⟶ 40.88 g

<em>x</em> = 40.88 – 29.05 = 11.83

<em>Step 2</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Co to O.

<em>Moles of Co</em> = 29.05 g Co × (1 mol Co /(58.93 g Co) = 0.492 96 mol Co

<em>Moles of </em>O = 11.83 g O × (1 mol O/16.00 g O) = 0.739 38 mol O

<em>Step 3</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smaller number of moles

Co:O = 0.429 26:0.739 38 = 1:1.4999

<em>Step 4</em>. Multiply each number by a factor that makes the <em>ratio close to whole numbers </em>

Multiply by 2. Then

Co:O = 2:2.998 ≈ 2:3

<em>Step 5</em>: Write the <em>empirical formula</em>

EF = Co₂O₃

4 0
3 years ago
Cl2(g) + 2kbr(aq)= 2kcl(aq) + Br2(I)
kotegsom [21]
Good the equation is balanced already
8 0
3 years ago
Oxygen 22 has a half life of 2.25 seconds. What percent of the sample is left after 2.25 seconds?
Nonamiya [84]

Answer:

50 because it’s a ratio problem

Explanation:

6 0
3 years ago
Read 2 more answers
Working principles of lithium/solid electrolytes batteries​
saw5 [17]

Answer:

The electrolyte carries positively charged lithium ions from the anode to the cathode and vice versa through the separator. The movement of the lithium ions creates free electrons in the anode which creates a charge at the positive current collectors

8 0
2 years ago
Magnesium (average atomic mass = 24.3050 amu) consists of three isotopes with masses 23.9850 amu, 24.9858 amu, and 25.9826 amu.
iris [78.8K]

Answer: The first isotope has a relative abundance of 79% and last isotope has a relative abundance of 11%

Explanation: Given that the average atomic mass(M) of magnesium

= 24.3050amu

Mass of first isotope (M1) = 23.9850amu

Mass of middle isotope (M2)=24.9858amu

Mass of last isotope(M3)= 25.9826amu

Total abundance = 1

Abundance of middle isotope = 0.10

Let abundance of first and last isotope be x and y respectively.

x+0.10+y =1

x = 0.90-y

M = M1 × % abundance of first isotope + M2 × % of middle isotope +M3 ×% of last isotope

24.03050= 23.985× x + 24.9858 ×0.10 + 25.9826×y

Substitute x= 0.90-y

Then

y = 0.11

Since y=0.11, then

x= 0.90-0.11

x=0.79

Therefore the relative abundance of the first isotope = 11% and the relative abundance of the last isotope = 79%

5 0
3 years ago
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