Since glycolysis of one glucose molecule generates two acetyl CoA molecules, the reactions in the glycolytic pathway and citric acid cycle produce six CO2 molecules, 10 NADH molecules, and two FADH2 molecules per glucose molecule
Answer:
The final volume should be 22 mL
Explanation:
For this problem, we will use the dilution equation:
C1*V1 = C2*V2
<u>Step 1</u>: Data given
with C1 = the initial concentration C1 = 0.220 mg/L
with V1 = the initial volume = 10 mL = 10 * 10^-3 L
with C2 = the final concentration = 0.100 mg/L
with V2 = the final volume = TO BE DETERMINED
<u>Step 2</u>: Calculating the final volume
C1*V1 = C2*V2
0.220 mg/L * 10*10^-3 L = 0.100 mg/L * V2
V2 = (0.220 mg/L * 10*10^-3 L) / 0.100 mg/L
V2 =0.022 L = 22 mL
The final volume should be 22 mL
Answer:
A. Their numbers of atoms
Explanation:
a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).
b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)
<h3>What is the molar mass?</h3>
The molar mass is the mass in grams of 1 mole of particles, that is, the mass in grams of 6.02 × 10²³ particles. The units are g/mol.
We want to calculate the number of moles represented by different masses of different substances. In each case, the conversion factor between mass and moles is the molar mass.
- a. 2.00 × 10² g of silver (Ag)
The molar mass of silver is 107.87 g/mol.
2.00 × 10² g × (1 mol/107.87 g) = 1.85 mol
- b. 37.1 g of silicon dioxide (SiO₂)
The molar mass of silicon dioxide is 60.08 g/mol.
37.1 g × (1 mol/60.08 g) = 0.618 mol
a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).
b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)
Learn more about molar mass here: brainly.com/question/21334167
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