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scoray [572]
2 years ago
11

What does stoichiometry use to relate moles of one molecule to moles of

Chemistry
1 answer:
Shkiper50 [21]2 years ago
6 0
It is A I took it befor hope this helps:)
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CAVA Chemistry 302/303B Unit 2 Lab Report
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1 property

2 procedure

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Which system is responsible for carrying oxygen to the muscle
Nitella [24]
Well red blood cells carry oxygen to muscles
Circulatory system is probably the answer you are looking for. 
7 0
3 years ago
Read 2 more answers
Q1.
dlinn [17]

Answer:

there are four peaks in the 13c NMR (B)

3 0
3 years ago
Equation is balanced already
mojhsa [17]

Answer:

1.) 13 g C₄H₁₀

2.) 41 g CO₂

Explanation:

To find the mass of propane (C₄H₁₀) and carbon dioxide (CO₂), you need to (1) convert mass O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles C₄H₁₀/CO₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles C₄H₁₀/CO₂ to mass C₄H₁₀/CO₂ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answers should have 2 sig figs to match the sig figs of the given value.

Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)

Molar Mass (C₄H₁₀): 58.124 g/mol

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

Molar Mass (O₂): 2(15.998 g/mol)

Molar Mass (O₂): 31.996 g/mol

2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O

 48 g O₂             1 mole             2 moles C₄H₁₀            58.124 g
---------------  x  -----------------  x  -------------------------- x  ------------------  =  
                         31.996 g              13 moles O₂               1 mole

=  13 g C₄H₁₀

 48 g O₂             1 mole               8 moles CO₂            44.007 g
---------------  x  -----------------  x  -------------------------- x  ------------------  =  
                         31.996 g              13 moles O₂               1 mole

=  41 g CO₂

6 0
1 year ago
HRISTINA HERRERA: Attempt 1
Lunna [17]

Answer:

7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.

Explanation:

Here we have the check if the mass of the reactants is equal to the mass of the products.

Reactants

7.5+50=57.5\ \text{g}

Products

57.5\ \text{g}

The data is consistent with the law of conservation of matter.

Reactants

50+243=293\ \text{g}

Products

206+97=303\ \text{g}

The data is not consistent with the law of conservation of matter.

Reactant

17.7+34.7=52.4\ \text{g}

Products

62.4\ \text{g}

The data is not consistent with the law of conservation of matter.

Only the first data is consistent with the law of conservation of matter.

8 0
3 years ago
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