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3 years ago

5

Need to find surface area

2 answers:

quester [9]3 years ago

5 0

Find the area for each shape.

For the triangle face you would do 4 times 6 divided by 2. Then times it by 2 because there are two triangle faces.

For the rectangle face do 5 times 12, then times 3 because there are 3 triangle faces.

Finally add both numbers together to get the surface area.

goldenfox [79]3 years ago

3 0

You have to break it down into their individual shapes
1st there are two triangles
To find the area for one of them
1/2bh. Or 1/2(4)(6()=12
Multiply the 12 by 2
The area for both triangles are 24
Although there are three triangles, you have to realize that only two of them have the same area
The base is 6*12=72 and there is only one of them
The two side rectangles are
5*12=60 multiply by 2 since there are 2
120

Add all of the areas together
24+72+120=216
Surface area 216 u^2

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Write an equation of a line in a slope-intercept form that passes through (-2,1) with a slope of 5.

KonstantinChe [14]

If they give you a point and slope, use point slope form.
Then simplify to get slope intercept form (y = mx + b)
slope (m) = 5
(-2, 1)

y - y1 = m(x - x1)
y - 1 = 5(x + 2)
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8 0

3 years ago

Х- а<br>x-b<br>If f(x) = b.x-a÷b-a + a.x-b÷a - b<br>Prove that: f (a) + f(b) = f (a + b)

GenaCL600 [577]

Given:

Consider the given function:

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}$

To prove:

$f(a)+f(b)=f(a+b)$

Solution:

We have,

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}$

Substituting $x=a$ , we get

$f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}$

$f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}$

$f(a)=0+a$

$f(a)=a$

Substituting $x=b$ , we get

$f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}$

$f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}$

$f(b)=b+0$

$f(b)=b$

Substituting $x=a+b$ , we get

$f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}$

$f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}$

$f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}$

$f(a+b)=\dfrac{b^2-a^2}{b-a}$

Using the algebraic formula, we get

$f(a+b)=\dfrac{(b-a)(b+a)}{b-a}$ $[\because b^2-a^2=(b-a)(b+a)]$

$f(a+b)=b+a$

$f(a+b)=a+b$ [Commutative property of addition]

Now,

$LHS=f(a)+f(b)$

$LHS=a+b$

$LHS=f(a+b)$

$LHS=RHS$

Hence proved.

5 0

3 years ago

9,513 rounded to the nearest thousand

zhenek [66]

9513 rounded to the nearest thousandth is 10,000.

I hope that helped! :>

4 0

4 years ago

Read 2 more answers

Dylan buys 3.2 pounds of grapes for $2.56. What is the price per pound of the grape.

Bess [88]

Answer:

$1.25

Step-by-step explanation:

3.2/2.56=1.25

5 0

4 years ago

Solve the linear system of equations using addition. Graph the equations to verify your solution. required.

zhenek [66]

<h3>Answer:</h3>

infinite solutions

<h3>Step-by-step explanation:</h3>

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Add 4x -y to both sides.

... -4x +y +4x -y = -4x +y +4x -y

... 0 = 0 . . . . . true for all values of x (or y)

Both equations describe the same line.

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The graph shows the first equation as a red line. The second equation is shown using a "blue dot" texture, so you can see it overlays the red line.

8 0

3 years ago