Answer:
Lane sold 34 homes.
Nanda sold 102 homes.
Step-by-step explanation:
This question can be solved by a system of equations.
I am going to say that:
Nanda sold x homes
Lane sold y homes
Over the past 6 months they sold 136 homes.
This means that 
Nanda sold 3 times as many homes as Lane.
This means that 
Replacing in the first equation:




Lane sold 34 homes.

Nanda sold 102 homes.
Answer:
They let you know the number of numbers there are/will be.
Step-by-step explanation:
Mono, being one, means there will only be one number is the equation.
Bi, being two, means there will be two numbers in the equation.
and tri, being three, means there are three numbers in the equation.
Answer:
ok lol
Step-by-step explanation:
9514 1404 393
Answer:
- late only: 15
- extra-late only: 24
- one type: 43
- total trucks: 105
Step-by-step explanation:
It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.
For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.
Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.
__
a) 15 trucks carried only late
b) 24 trucks carried only extra late
c) 4+15+24 = 43 trucks carried only one type
d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out
B is the correct answer since the greatest common factor is the greatest common divisor