Answer:

Explanation:
Given that;
Thermal diffusivity 
Thermal conductivity 
Heat transfer coefficient h = ( we are to assume the imposed surface temperature ) = 20 W/m².K
Initial temperature = 150 ° C = (150+273) K = 423 K
Then coolant temperature with which the casting is exposed to = 20° C = (20+273)K = 293 K
Time = 40 seconds
Length = 20mm = 0.02 m
The objective is to determine the temperature at the surface at a depth of 20 mm after 40 seconds.


Bi == 0.02



For a wall at 0.2 Bi


Therefore;











Answer: speaks Portuguese
Eu disse a todos a tradução para que possam te ajudar
Explanation: Y’all can help I have no idea
QUESTION 13. Explain the use of quotation marks in the excerpt "I will give each of you
seed. The one who will bring me the most beautiful flower within six months will be chosen but
wife and the future empress of China. ".
QUESTION 14. The palace servant considered the idea of her daughter attending the celeb
organized by the prince of the region, a foolish idea, a madness. This is an OP
Do you agree with this opinion of the character? Justify your answer.
Answer:
water released through the bottom of the reservoir in 24 hrs is 1992 ha-cm
Explanation:
Given the data in the question;
A = 200 hectare = 2 × 10⁶ m²
water evaporated Ve = 2 × 10⁶ m² × 3 × 10⁻² = 60000 m³ { in 24 hrs }
Water added by storm in 24hrs Vi = 3 × 24 × 3600 = 259200 m³
now let water released be Vr
ΔV = V_ini - V_final = 0
Vi - Ve - Vr = 0
Vr = Vi - Ve
Vr = 259200 m³ - 60000 m³
Vr = 199200 m³ = 19920000 m² - cm
Vr = 1992 ha-cm
Therefore, water released through the bottom of the reservoir in 24 hrs is 1992 ha-cm
Answer:
s(2v₁+v₂+v₃)/4
Explanation:
Recall that relationship between speed,distance and time is expressed as
speed=distance/time.
For the first part of the journey travelled at a speed of V₁ and covered a distance of (s/2), the time taken t₁=(s/2)/v₁
for the second part of the journey,let the time taken to complete both half of the second journey be t₂ and t₃ respectively. since it travel each half each distance at equal half time,then
t₂₌t₃
let the distance of the second journey be (s/2), where each time complete (s/4) distance. the time taken is
t₂₌(s/4)/v₂ and t₃=(s/4)/v₃
hence the total time taken is to cover the distance s is
t=t₁+t₂+t₃
t=(v₁s/2)+ (v₂s/4)+(v₃s/4)
t=s(2v₁+v₂+v₃)/4
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.