Answer:
A) β_max = 20.64
B) TH = 68.25°C
C) TC = 54.27°C
Explanation:
A) We are given;
TH = 16°C = 16 + 273K = 289K
TC = 2°C = 2 + 273K = 275K
Formula for maximum cycle coefficient of performance is given as;
β_max = TH/(TH - TC)
β_max = 289/(288 - 275)
β_max = 20.64
B) We are given;
Heat rejected to system at hot reservoir; Q_H = 10.5 KW
Heat provided to system at cold reservoir; Q_C = 8.75 KW
Cold reservoir temperature; TC = 0°C = 0 + 273K = 273K
Formula for actual cycle COP is given as;
β_actual = Q_C/W_cycle
Where W_cycle is the work done and is given by;
W_cycle = Q_H - Q_C
W_cycle = 10.5 - 8.75 = 1.75 KW
Thus,
β_actual = 8.75/1.75
β_actual = 5
Actual cycle COP is defined as;
β_actual = TH/(TH - TC)
And we are looking for TH.
Thus,
TH = TC/(1 - (1/β_actual))
TH = 273/(1 - 1/5)
TH = 273/(4/5)
TH = 341.25K = 341.25 - 273°C = 68.25°C
C) We are given;
TH = 27°C = 27 + 273 = 300°C
β_max = 12
Thus, from,
β_max = TH/(TH - TC)
TC = TH(1 - (1/β_max))
TC = 300/(1 - 1/12)
TC = 327.27K = 327.27 - 273 °C = 54.27°C
Answer:
YES
Explanation:
values other than five will work
Answer & Explanation:
(a) Frequency of 2Hz is applied to a sampler/zero-order hold combination
The sampling rate is 10Hz
List of all the frequencies present in the output that are less than 50Hz.
Adding:
fs + fm = 10 + 2
= 12 Hz
2fs + fm = 2 * 10 + 2
= 22 Hz
3fs + fm = 3 * 10 + 2
= 32 Hz
4fs + fm = 4 * 10 + 2
= 42 Hz
Subtracting:
fs - fm = 10 - 2
= 8 Hz
2fs - fm = 2 * 10 - 2
= 18 Hz
3fs - fm = 3 * 10 - 2
= 28 Hz
4fs - fm = 4 * 10 - 2
= 38 Hz
5fs - fm = 5 * 10 - 2
= 48 Hz
(b) Frequency of 8Hz is applied to a sampler/zero-order hold combination
The sampling rate is 10Hz
List of all the frequencies present in the output that are less than 50Hz.
Adding:
fs + fm = 10 + 8
= 18 Hz
2fs + fm = 2 * 10 + 8
= 28 Hz
3fs + fm = 3 * 10 + 8
= 38 Hz
Subtracting:
fs - fm = 10 - 8
= 2 Hz
2fs - fm = 2 * 10 - 8
= 12 Hz
3fs - fm = 3 * 10 - 8
= 22 Hz
4fs - fm = 4 * 10 - 8
= 32 Hz
5fs - fm = 5 * 10 - 8
= 42 Hz
Basic robots are entirely mechanical. However, when the need arises for automation the 'mechanical' way of solving the design is not adequate for other areas of technology, particularly electronics, optoelectronics, materials engineering, especially computer science.
Answer:
b
Explanation:
a) ADC is located on DAQ filter but not the reconstruction filter
b) to remove aliasing, the sampling rate must be greater than or equal ot twice the highest frequency component in the input signal. In other words, all frequencies in input sgnal are less than fs/2. Therefore, frequencies greater than fs/2 are removed by anti-aliasing filter
c) the DAC can have different sampling rate from ADC