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HACTEHA [7]
3 years ago
12

A particle travels rectilinearly a ceertain distance s. The particle travels half the distance (s/2) at a velocity v1. It travel

s the remaining distance (s/2) at a velocity v2 for half the time and a velocity v3 for the other half of the time.
1. What is the total time taken to travel the distance s?
Engineering
1 answer:
lara31 [8.8K]3 years ago
6 0

Answer:

s(2v₁+v₂+v₃)/4

Explanation:

Recall that relationship between speed,distance and time is expressed as

speed=distance/time.

For the first part of the journey travelled at a speed of V₁ and covered a distance of (s/2), the time taken t₁=(s/2)/v₁

for the second part of the journey,let the time taken to complete both half of the second journey be t₂ and t₃ respectively. since it travel each half each distance at equal half time,then

t₂₌t₃

let the distance of the second journey be (s/2), where each time complete (s/4) distance. the time taken is

t₂₌(s/4)/v₂ and t₃=(s/4)/v₃

hence the total time taken is to cover the distance s is

t=t₁+t₂+t₃

t=(v₁s/2)+ (v₂s/4)+(v₃s/4)

t=s(2v₁+v₂+v₃)/4

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scrapers are used to haul dirt from a borrow pit to the cap of a landfill. the estimated cycle time for the scrapers is 9.5 minu
ladessa [460]
Answer is: 12.8 because when you multiply it by the 2nd power of 8 then the scraper equals to be 12.8 in height and that’s how much each scraper requires to operate :)
7 0
3 years ago
Explain 3 types of lubrication occurs in bearings?
Angelina_Jolie [31]

Answer:

The three types of lubrication occurred in the bearing are:

When the lubrication occur in the bearing it play an important role in the rolling life of bearing element. Basically, lubricant task is to reduced the friction.

1) Grease lubricant: Grease contain various type of additives which help in enhance the performance. It consist of oil where thickness are added as, this thickness improved the characteristics of grease.

2) Oil lubricant: This is used to reduced or minimized the friction and the lubricant oil is used to in those vehicles when they are motorized. Bearing lubricant oil is used to higher the speed capability.

3) Solid films: These are non fluid coating surface that are applied in the friction surface for prevention. It is used in very extreme situation where oil and grease types of lubricant does not work.  

8 0
3 years ago
One kilogram of water fills a 0.140 m^3 rigid container at an initial pressure of 1.8 MPa. The container is then cooled to 40°C.
Pavel [41]

Answer:

T1 = 299.18 °C

P2 = 0.00738443 MPa

Explanation:

From the data, we can get two properties for the initial condition. These are pressure and specific volume.

The pressure is 1.8 MPa and the specific volume, we can get it with the mass and volume of the container, since it’s filled this is also the volume of the water in it.

v=\frac{vol (m^{3})}{mass (kg)} = \frac{0.140 m^{3}}{1 kg} = 0.140 \frac{ m^{3}}{kg}

When we check in the thermodynamic tables, the conditions for saturation at 1.8 MPa we found the following:

P^{sat} = 1.8 MPa

T^{sat} = 207.12 C

v_{g} = 0.1103\frac {m^{3}}{kg} specific volume for the saturated vapor  

v_{l} = 0.001167 \frac{m^{3}}{kg} specific volume for the saturated liquid  

Since the specific volume in our condition is higher that the specific volume for the saturated vapor, we have a superheated steam.  

Looking in the thermodynamic tables for superheated steam we found that the temperature where the steam has a specific volume of 0.140 \frac{ m^{3}}{kg} at 1.8 MPa is 299.18 °C. This is the initial temperature in the container.

Since the only information that we have about the final condition is that the container was cooled. We can assume that it was cooled until a condition of saturation. So, the final pressure for the water will be the pressure of saturation for a temperature of 40°C. From thermodynamic tables we get:

P^{sat} at 40C = 0.00738443 MPa

7 0
3 years ago
What factors are likely to promote the formation of stress corrosion cracks?
Naddika [18.5K]

Answer:

Stress corrosion cracking

Explanation:

This occurs when susceptible materials subjected to an environment that causes cracking effect by the production of folds and tensile stress. This also depends upon the nature of the corrosive environment.

Factors like high-temperature water, along with Carbonization and chlorination, static stress, and material properties.

7 0
4 years ago
Carbon dioxide (CO2) is used in industrial and research application, and is sometimes stored at very high pressure in rigid meta
12345 [234]

Answer:

a)m =  247.43 kg

b) m = 123.71 kg

Explanation:

a)

Given data:

volume  =0.8 m^3

P =  18,000 kPa

T =35 degree C = 308 K

By ideal gas equation we have following relation

PV = mRT

where R is gas constant

R = \frac{8.314}{44} = 0.18895 kJ/ kg K

m =\frac{PV}{RT}

m = \frac{18000\times 0.8}{0.18895 \times 308}

m = 247.43 kg

b)

when pressure = 9000 kPa

from ideal gas equation

PV = mRT

where R is gas constant

R = \frac{8.314}{44} = 0.18895 kJ/ kg K

m =\frac{PV}{RT}

m = \frac{9000\times 0.8}{0.18895 \times 308}

m = 123.71 kg

3 0
3 years ago
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