Answer:
New volume of the balloon will be 28.4 L.
Explanation:
As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:
where 
and 
are volume of gas at 
and 
temperature (in kelvin scale) respectively.
Here 
, 
and 
So 
= 28.4 L
So new volume of the balloon will be 28.4 L.
<span>rusting of ironcombustion (burning) of woodmetabolism of food in the body<span>mixing an acid and a base, such as hydrochloric acid (HCl) andsodium hydroxide (NaOH)</span>cooking an eggdigesting sugar with the amylase in saliva<span>mixing baking soda and vinegar to produce carbon dioxide gas</span>baking a cakeelectroplating a metal<span>using <span>a </span>chemical battery</span>explosion of fireworksrotting bananasgrilling a hamburger<span>milk going sour</span></span>
C is the correct answer. For nonmetal-nonmetal compounds, use the Greek prefixes
Mono - 1
Di - 2
Tri - 3
Tetra - 4
Penta - 5
Hexa - 6
Hepta - 7
And so on...
The reason D is not right is because a and o cannot be next to each other in between prefix and element.
Hope this helps!
The radio active decay of a substance or any chemical is measured in half-lives because of the period where there are significant changes in the amount of the chemicals. The amount of chemical is almost halved in the next period as is suggested by the given graph.
Answer:
8.28 MPa
Explanation:
From the question given above, the following data were obtained:
Radius (r) = 2×10¯³ m
Force applied (F) = 104 N
Pressure (P) =?
Next, we shall determine the area of the nail (i.e circle). This can be obtained as follow:
Radius (r) = 2×10¯³ m
Area (A) of circle =?
Pi (π) = 3.14
A = πr²
A = 3.14 × (2×10¯³)²
A = 3.14 × 4×10¯⁶
A = 1.256×10¯⁵ m²
Next, we shall determine the pressure. This can be obtained as follow:
Force applied (F) = 104 N
Area (A) = 1.256×10¯⁵ m²
Pressure (P) =?
P = F / A
P = 104 / 1.256×10¯⁵
P = 8280254.78 Nm¯²
Finally, we shall convert 8280254.78 Nm¯² to MPa. This can be obtained as follow:
1 Nm¯² = 1×10¯⁶ MPa
Therefore,
8280254.78 Nm¯² = 8280254.78 Nm¯² × 1×10¯⁶ MPa / 1 Nm¯²
8280254.78 Nm¯² = 8.28 MPa
Thus, the pressure exerted on the wall is 8.28 MPa
