Explanation:
The given data is as follows.
Boiling point of water (
= (100 + 273) K = 323 K,
Boiling point of solution (
= (101.24 + 273) K = 374.24 K
Hence, change in temperature will be calculated as follows.

= 374.24 K - 323 K
= 1.24 K
As molality is defined as the moles of solute present in kg of solvent.
Molality = 
Let molar mass of the solute is x grams.
Therefore, Molality = 
m =
= 
As, 

x = 
= 1321.29 g
This means that the molar mass of the given compound is 1321.29 g.
It is given that molecular formula is
.
As, its empirical formula is
and mass is 30 g/mol. Hence, calculate the value of n as follows.
n = 
= 
= 44 mol
Thus, we can conclude that the formula of given material is
.
All vascular plants have vascular tissue which allows the transport of water, nutrients and food between the ground and the body of the plant. So your answer would be that the internal structures of vascular plants transport food and water through their vascular tissue. Hope this helps!<span />
Here is the link to the answer:
Answer:
D
Explanation:
I think but it is an better attempt than the other guy answer.