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Dahasolnce [82]
3 years ago
14

The differential distribution of ions across the cell membrane is due to the:

Physics
1 answer:
DIA [1.3K]3 years ago
8 0

The differential distribution of ions across the cell membrane is due to the "resting membrane potential".

<u>Option: C</u>

<u>Explanation:</u>

The unequal allocation of charged particles like ions between the internal and external portion of cell, and by the varying membrane permeability to various ion forms, understood as resting membrane potential.

Within a sleeping brain, Na+ and K+ ions exhibit concentration gradients throughout the membrane, which push their gradients down through channels, resulting in a differentiation of the charges that generates the resting potential. With K+ than Na+ ions, the membrane is even more permeable, so the resting potential is similar to potassium ion's equilibrium potential.

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An oscillator consists of a block of mass 0.628 kg connected to a spring. When set into oscillation with amplitude 27 cm, the os
oksian1 [2.3K]

Answer:

T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N

Explanation:

a.)

Period: It is already given in the question "oscillator repeats its motion every 0.372 s".

So T=0.372 s

b)

frequency= f = 1/ T

f = 1/ 0.372

f=2.7 Hz

c).

Angular frequency= w= 2πf

w= 2*π*2.7

w=16.9 rad/s

d)

Spring Constant:

As w=\sqrt{k/m}

⇒w²= k/m

⇒k= m*w²

⇒k= 0.628 * 16.9² N/m

⇒k=179.2 N/m

e)

The mass will have maximum speed when it passes through the mean position.

At mean position

Maximum elastic potential energy = Maximum kinetic energy

1/2 k A² = 1/2 m v²    ( A is amplitude of oscillation)

⇒ v=\sqrt{k A^2/m}

⇒ v= \sqrt{179.2 * 0.27/ 0.628}\

⇒ v= 8.78 m/s

f)

Maximum force will be exerted on the block when it is at maximum distance.

F= k* A   ( A is amplitude of oscillation)

F= 179.2 * 0.27 N

F= 48.4 N

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Explanation:

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Answer:

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