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TEA [102]
3 years ago
12

Can a nickel be attracted to a magnet?

Physics
1 answer:
zhuklara [117]3 years ago
8 0
Yes... This is a question google could answer. Just Saying
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Which best describes Earth's magnetic pole?
goblinko [34]

Answer:

b

Explanation:

because with no pole there is no role

7 0
3 years ago
Read 2 more answers
If the acceleration of the projective is: a = c s m/s 2 Where c is a constant that depends on the initial gas pressure behind th
Sedbober [7]

Answer:

c = 4,444.44

Explanation:

You have the following expression for the acceleration of the projectile:

a=cs   (1)

s: distance to the ground of the projectile

To find the value of the constant c you use the following formula:

v^2=v_o^2+2a \Delta s   (2)

vo: initial  velocity = 0 m/s

v: final speed = 200 m/s

Δs: distance traveled by the projectile = 3m - 1.5m = 1.5m

You replace the expression (1) into the expression (2):

v^2=2(cs)\Delta s

You do the constant c in the last equation, then you replace the values of v, s and Δs:

c=\frac{v^2}{2s\Delta s}=\frac{(200m/s)^2}{2(3m/s^2)(1.5m)}=4444.44

6 0
3 years ago
Find the torque required for the shaft to transmit 40 kW when (a) The shaft speed is 2500 rev/min. (b) The shaft speed is 250 re
Luba_88 [7]

Answer:

(a) 152.85 Nm

(b) 1528.5 Nm

Explanation:

According to the formula of power

P = τ ω

ω = 2 π f

(a) f = 2500 rpm = 2500 / 60 = 41.67 rps

So, 40 x 1000 = τ x 2 x 3.14 x 41.67

τ = 152.85 Nm

(b) f = 250 rpm = 250 / 60 = 4.167 rps

So, 40 x 1000 = τ x 2 x 3.14 x 4.167

τ = 1528.5 Nm

3 0
3 years ago
HELP ME PLEASE URGENT WILL MARK AND 5 STARS
Artist 52 [7]

Answer:

option (B) is the correct option.

please thanks me and follow me

7 0
3 years ago
two cars are moving at constant speeds in a straight line along a major highway. The first is travelling at 20ms^-1 and the seco
Reika [66]

Answer:

t=750s

Explanation:

The two cars are under an uniform linear motion. So, the distance traveled by them is given by:

\Delta x=vt\\x_f-x_0=vt\\x_f=x_0+vt

x_f is the same for both cars when the second one catches up with the first. If we take as reference point the initial position of the second car, we have:

x_0_1=6km\\x_0_2=0

We have x_f_1=x_f_2. Thus, solving for t:

x_0_1+v_1t=x_0_2+v_2t\\x_0_1=t(v_2-v_1)\\t=\frac{x_0_1}{v_2-v_1}\\t=\frac{6*10^3m}{28\frac{m}{s}-20\frac{m}{s}}\\t=750s

8 0
3 years ago
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