Answer:
2500 and kg its is very easy do with method
Answer:
Less than Mercury's
Explanation:
According to third Kepler's law, the square of the planet's orbital period is proportional to the cube of the average orbital radius of the planet's orbit. The constant of proportionality depends only on the mass of the star, recall that 51 Peg has the same mass as the Sun. Since the orbital period of this planet is less than Mercury's, its average orbital radius is less than Mercury's.
Answer:
The orbital speed of this second satellite is 5195.16 m/s.
Explanation:
Given that,
Orbital radius of first satellite 
Orbital radius of second satellite 
Mass of first satellite 
Mass of second satellite 
Orbital speed of first satellite = 4800 m/s
We need to calculate the orbital speed of this second satellite
Using formula of orbital speed
From this relation,
Now, 
Put the value into the formula
Hence, The orbital speed of this second satellite is 5195.16 m/s.
Let's use Newton's 2nd law of motion:
Force = (mass) x (acceleration)
Force = (68 kg) x (1.2 m/s²) = 81.6 newtons .
Answer: The first electromagnet has a more powerful current than
the second
Explanation:
Since the two electromagnets contain the same types of magnets and wires. If the magnet In the first moves much faster than the second. Therefore:
The first electromagnet has a more powerful current than the second
Because the induced EMF is proportional to the induced current.
Where the induced EMF depends on the speed of the magnet according to the formula below
EMF = BVL
So, increase in speed of the magnet will cause more powerful induced current and emf
