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3 years ago

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A patient is administered 20 mg of iodine-131. How much of this isotope will remain in the body after 40 days if the half-life f

or iodine-131 is 8 days?

1 answer:

igor_vitrenko [27]3 years ago

4 0

The formula for half-life is:

$A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h}}$

Where A is the amount of iodine-131 initially and after 40 days, t is time, h is half-life of the isotope. Let's plug in our values to the equation:

$A_{final}=20(\frac{1}{2})^{\frac{40}{8}=0.625g$

Therefore, the patient has 0.625 grams of iodine-131 after 40 days.

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