this question is unclear. please specify.
Answer:
v₂ = 5131.42 m/s
Explanation:
given,
radius of the planet = r₁ = 9.00×10⁶ m
mass of the satellite = m₁ = 68 Kg
orbital radius = r₁ = 8 x 10⁷ m
orbital speed = v₁ = 4800 m/s
mass of second satellite = m₂ = 84.0 kg
orbital radius = r₂ = 7.00×10⁷ m
orbital speed of second satellite = v₂ = ?
using orbital speed of satellite
so,
now,
v₂ = 5131.42 m/s
The orbital speed of second satellite is equal to v₂ = 5131.42 m/s
At New Moon the percent illuminated is 0; at First and Last Quarters it is 50%; and at Full Moon it is 100%<span>. During the crescent phases the percent illuminated is between 0 and </span>50%<span> and during gibbous phases it is between </span>50%<span> and </span>100%<span>.
so it depends on the phase
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I believe the answer is D: Work. PV is the formula for work.
The formula used for finding the tangential speed (speed of something that is moving in a circular path) of an orbiting object is:
V₍t₎ = ωr
V₍t₎ = tangential speed or velocity
ω = angular velocity
r = radius of the circular path
if time taken t is only given then use this formula to calculate the tangential speed:
V₍t₎ = 2πr/t, t is time taken
