Answer:
No. Twice as much work will give the ball twice as much kinetic energy. But since KE is proportional to the speed squared, the speed will be
times larger.
Explanation:
The work done on the ball is equal to the kinetic energy gained by the ball:

So when the work done doubles, the kinetic energy doubles as well:

However, the kinetic energy is given by

where
m is the mass of the ball
v is its speed
We see that the kinetic energy is proportional to the square of the speed,
. We can rewrite the last equation as

which also means

If the work is doubled,

So the new speed is

So, the speed is
times larger.
The term which is considered as being undefined is referred to as a point and is therefore denoted as option A in this context.
<h3>What is a Point?</h3>
This is defined as as small round mark written on a plane which signifies the position or location of a substance. This can also be seen as a dot and is also used to separate a group of numbers such as in the case of decimals etc.
It is referred to as being undefined alongside a plane, line etc as a result of it only being explained using specific examples and descriptions unlike a segment which can be viewed and understood easily when working on the parameter.
This is therefore the reason why a point is undefined and the most appropriate choice.
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Answer:
A change in color
The formation of a precipitate
A clear liquid becoming cloudy
The formation of bubbles
The formation of smoke
Explanation:
A chemical reaction can be defined as the conversion of reactant into product. The process in which one or more than one substance is converted into one or many different substances.
There are some indications which can provide the evidence that chemical reaction has occurred.
A change in color of the substance, formation or smoke or bubbles. The formation of the precipitate and in case the substance becomes cloudy.
All these evidences show that chemical reaction has occurred.
The work done by gas is 0.753 J and change in internal energy is 4.247J
So we are given that mass is 2kg , radius 1 cm and the amount of heat is 5 cm
The piston raised by 2.4cm
As we know that Work done is PΔV
Where ΔV is change in volume
Therefore ΔV = πr^2 h = π x (.01)^2 x .024 =7.53×10^(-6)m^3
Here pressure is 10^5 pa
So W = 
Therefore W = 0.753 J
Now coming to change in internal energy
Change in Internal Energy = Heat Added - Energy lost in work
∴ 5J - 0.753 J = 4.247J
Hence the change in internal energy is 4.247 J
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