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Taya2010 [7]
3 years ago
14

4. Um chuveiro elétrico instalado em uma rede de

Physics
1 answer:
gulaghasi [49]3 years ago
6 0

Answer:

<em />

  • <u>1.1 kilowatt-hour</u>

Explanation:

The question is:

  • <em>4. An electric shower installed in a network of 220 V, when in operation, is traversed by an electric current of intensity 20 A. Determine the electrical energy consumed, in kilowatt-hour, during a bath lasting 15 min.</em>

<u>1. Data:</u>

<u />

a) V = 220V

b) I = 20 A

c) E = ?

<u>2. Physical principles and formulae</u>

Power, P, is equal to the product of the potential difference, V, by the current, I:

          P=V\times I

The energy, E, is equal to the product of the power, P, and the time, t:

         E=P\times t

<u>3. Solution</u>

         P=220V\times 20A=4,400W=4,400J/s

        E=4,400W\times 15min\times 1hour/60min=1,100W-h=1.1kwatt-hour

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Answer:

0.83 ω

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Moment of inertia of the first flywheel , I = 0.5 MR²

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I x ω = ( I + I') x ω'

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0.5 x MR² x ωo = 0.6 MR² x ω'

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Light shines through a single slit whose width is 5.7 x 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a
lilavasa [31]

Answer:

\lambda = 570\ nm

Explanation:

Given,

Width of slit, W = 5.7 x 10⁻⁴ m

Distance between central bright fringe, L = 4 m

distance between central bright fringe and first dark fringe, y = 4 mm

Diffraction angle

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tan \theta = \dfrac{4}{4\times 10^3}

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