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Alex777 [14]
3 years ago
7

A sample of ice is heated continuously until it becomes a liquid, and then a gas. Its temperature is recorded throughout and a g

raph is constructed. During the transition from solid ice to liquid water the graph is flat indicating no increase in kinetic energy even though heat is still being added to the sample. What does this section represent?
A. The specific latent heat of vaporization
B. The specific heat
C. The specific latent heat of fusion
D. The internal energy
Chemistry
1 answer:
padilas [110]3 years ago
3 0

Answer:

The answer to your question is: C. The specific latent heat of fusion

Explanation:

A. The specific latent heat of vaporization  Specific latent heat of vaporization indicates the transition from liquid to vapor, but we are not looking for this definition. This answer is wrong.

B. The specific heat indicates the amount of heat needed to increase the temperature of water 1°C, so this answer is wrong.

C. The specific latent heat of fusion . This heat indicate the transition from solid ie to liquid, so this is the right answer.

D. The internal energy measures the energy of the molecules of a substance, so this answer is wrong.

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How much heat will a 45.00 g piece of glass require to change its temperature from 10 to 30 °C. The specific heat capacity is 0.
kolbaska11 [484]

Answer:

Q = 450 J

Explanation:

Given that,

Mass of a piece of glass, m = 45 g

The temperature changes from 10°C to 30°C.

The specific heat is 0.5 J/g°C

We need to find heat required to raise the temperature. The formula that is used to find it is given by :

Q=mc\Delta T\\\\Q=45\times 0.5\times (30-10)\\\\Q=450\ J

So, the required heat is 450 J. Hence, the correct option is (c).

6 0
2 years ago
Nickel carbonyl, Ni(CO)4 is one of the most toxic substances known. The present maximum allowable concentration in laboratory ai
vodomira [7]

<u>Answer:</u> The mass of Ni(CO)_4 allowable in the laboratory is 4599.5 grams

<u>Explanation:</u>

To calculate the volume of cuboid, we use the equation:

V=l\times b\times h

where,

V = volume of cuboid

l = length of cuboid = 14 ft

b = breadth of cuboid = 22 ft

h = height of cuboid = 9 ft

Putting values in above equation, we get:

V=14\times 22\times 9=2772ft^3=78503.04L     (Conversion factor:  1ft^3=28.32L

To calculate the moles of gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 78503.04 L

T = Temperature of the gas = 23^oC=[23+273]K=296K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

1.00atm\times 78503.04L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 296K\\\\n=\frac{1.00\times 78503.04}{0.0821\times 296}=3230.4mol

Applying unitary method:

For every 109 moles of gas, the moles of Ni(CO)_4 present are 1 moles

So, for 3230.4 moles of gas, the moles of Ni(CO)_4 present will be = \frac{1}{109}\times 3230.4=26.94mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of Ni(CO)_4 = 26.94 moles

Molar mass of Ni(CO)_4 = 170.73 g/mol

Putting values in above equation, we get:

26.94mol=\frac{\text{Mass of }Ni(CO)_4}{170.73g/mol}\\\\\text{Mass of }Ni(CO)_4=(26.94mol\times 170.73g/mol)=4599.5g

Hence, the mass of Ni(CO)_4 allowable in the laboratory is 4599.5 grams

3 0
3 years ago
C12H26+Oxygen=12CO2+water<br>calculate the mass of one mole of the liquid alkane C12H26.​
Inessa [10]

Answer:

170.38g is the mass of 1 mole of C₁₂H₂₆

Explanation:

To solve this question we must find the molar mass of the alkane C₁₂H₂₆. The molar mass is defined as the mass of one mole of a substance.

In 1 mole of C₁₂H₂₆ we have 12  moles of Carbon and 26 moles of Hydrogen. With the periodic table of elements we can know the molar mass of 1 mole of Carbon and 1 mole of hydrogen, and, thus, the molar mass of the alkane (Molar mass C = 12.01g/mol, H = 1.01g/mol)

<em>Molar mass C₁₂H₂₆:</em>

12C = 12*12.01g/mol = 144.12g/mol

26H = 26*1.01g/mol = 26.26g/mol

144.12g/mol + 26.26g/mol =

<h3>170.38g is the mass of 1 mole of C₁₂H₂₆</h3>
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