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BARSIC [14]
3 years ago
10

Which of the following is NOT a derived unit?a)

cm^{3}" alt="cm^{3}" align="absmiddle" class="latex-formula"> b) g/mL c)kg
Chemistry
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer:

The answer to your question is c) kg

Explanation:

Derived units is when to units are combined to get a new one, For example, combining length and length gives lenght² and then we measured area, this is a derived unit.

a) cm³ this answer is wrong because we are combining length x length x length so we get the units of volume, this is a derived unit.

b) g/mL this answer is wrong because we are combining mass and volume so we can measure density, this units are derived.

c)kg this answer is correct because it measures mass and only that, then it's a fundamental unit.

seraphim [82]3 years ago
4 0

Answer:

c) kg

Explanation:

Kilograms stands alone. It has to be hooked up to another unit for it to be a derived unit.

I am joyous to assist you anytime.

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8 0
1 year ago
A chemical reaction that releases heat to the surroundings is said to be __________ and has a __________ H at constant pressure
Savatey [412]

Answer:

The correct option is c) exothermic, negative.

Explanation:

Reactions that releases heat to the surroundings are called exothermic, and are characterized by negative entalpy (ΔH) values.

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3 years ago
What do cubic measurements, live cm3, mesure?"<br> O length<br> volume
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The answer is volume.
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A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a
Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

q=mc\Delta T

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

q_{released}=q_{absorbed}\\&#10;q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T

The given mass of calorimeter has been, m_{calorimeter}=1350\;\rm g

The specific heat of the calorimeter has been, c_{calorimeter}=5.82\;\rm J/g^\circ C

The change in temperature of the calorimeter has been, \Delta T=2.87^\circ \rm C

Substituting the values for heat released:

q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\&#10;q_{released}=22,549.5\;\text J\\&#10;q_{released}}=22.54\;\rm kJ

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0
2 years ago
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yarga [219]

Answer:

97.561 g/mol

Explanation:

8 0
3 years ago
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