Answer:
Mass, m = 7.97 grams
Explanation:
We have,
Initial temperature was 34 degrees Celsius
Heat produced in it is 100 calories of heat
The specific heat capacity of water is 4.18 J/g °C
The heat produced due to change in temperature is given by :

m is mass of water in grams

So, 7.97 grams of water is required to produce heat of 2200 joules.
Answer:
8.32 s⁻¹
Explanation:
Given that:
The concentration of myosin = 25 pmol/L
R_max = 208 pmol/L/s
The objective is to determine the turnover number of the enzyme molecule myosin, which has a single active site.
In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.
The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.
The turnover number of the enzyme molecule of myosin can be calculated by the expression: 
⇒ 
= 8.32 s⁻¹
Water, Water is not a pure substance. It is a mixture, and Chromatography
First, you have to know the chemical formula of ozone and oxygen gas. Oxygen gas is O₂; it is one of the few gases that are diatomic in nature. The chemical formula of ozone is O₃. In oxygen gas, there are 2 particles of the oxygen element, while there are 3 particles for the ozone. There might be a slight difference but this induces a great difference in their properties. Oxygen is essential to living things because this is the gas that we breathe in. However, ozone is not safe to breathe in. It is a very strong oxidizing agent, almost 4 times as strong as the oxygen. Its main function is to block the UV rays from entering the Earth's atmosphere which can be harmful to our health.
Having known their chemical formula and properties, we know that an oxygen gas has 2 particles of oxygen element. So, if there are 24 particles of oxygen gas, that would mean 48 particles of the oxygen element. Since an ozone compound contains 3 particles of the oxygen element, then 48/3 = 16. It would take 16 particles of ozone to form 24 particles of the oxygen gas.
Mass of methane takne = 1.5g
moles of methane used = masss / molar mass = 1.5 / 16 = 0.094 moles
mass of water = 1000 g
Initial temperature of water = 25 C
final temperature = 37 C
specific heat of water = 4.184 J /g C
1) Heat absorbed by water = q =m• C• ΔT = 1000 X 4.184 x (37-25) = 50208 Joules
2) Heat absorbed by calorimeter = Heat capacity X ΔT = 695 X (37-25) = 8340 J
3) Total heat of combustion = heat absorbed by water + calorimeter = 50208 + 8340 = 58548 Joules
This heat is released by 0.094 moles of methane
So heat released by one mole of methane =
- 622851.06 Joules = 622.85 kJ / mole
4) standard enthalpy of combustion = -882 kJ / mole
Error = (882-622.85) X 100 / 882 = 24.84 %