Taking into account the reaction stoichiometry, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
2 AgBr + Na₂S₂O₃ → Ag₂S₂O₃ + 2 NaBr
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- AgBr: 2 moles
- Na₂S₂O₃: 1 mole
- Ag₂S₂O₃: 1 mole
- NaBr: 2 moles
The molar mass of the compounds is:
- AgBr: 187.77 g/mole
- Na₂S₂O₃: 158 g/mole
- Ag₂S₂O₃: 327.74 g/mole
- NaBr: 102.9 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- AgBr: 2 moles ×187.77 g/mole= 375.54 grams
- Na₂S₂O₃: 1 mole ×158 g/mole= 158 grams
- Ag₂S₂O₃: 1 mole ×327.74 g/mole= 327.74 grams
- NaBr: 2 moles ×102.9 g/mole= 205.8 grams
<h3>Mass of Ag₂S₂O₃ formed</h3>
The following rule of three can be applied: if by reaction stoichiometry 375.54 grams of AgBr form 327.74 grams of Ag₂S₂O₃, 125 grams of AgBr form how much mass of Ag₂S₂O₃?
<u><em>mass of Ag₂S₂O₃= 109.09 grams</em></u>
Then, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.
Learn more about the reaction stoichiometry:
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<span>The atoms in a compound are held together by a chemical bond. The chemical bonds can be either covalent bonds or ionic bonds. Both the bonds are considered very strong bonds. These bonds are mainly formed by sharing of electrons or in the case when one of the elements making the compound donates electron to the other element. The nucleus of each atom attracts to form a strong bond. This property of attraction between the nucleus of the atoms actually helps in forming the chemical bonds. </span>
The
chemical reaction that occurs between the given substances is a neutralization
reaction as shown below :
H_2SO_4
+ 2KOH -> K_2SO_4 + 2H_2O
<span>1
mol 2 mol
1 mol 2 mol </span>
<span>The
number of moles of the given substances
is calculated as shown : </span>
Number
of moles of H_2SO_4 = 25.0 mL x 0.50 M = 12.5 millimoles
Number
of moles of KOH = 25.0 mL x 1.00 M = 25.0 millimoles
As 1
mol of sulfuric acid reacts with 2 mol of KOH to give 2 mol of water, 12.5
millimoles of sulfuric acid completely reacts with 25.0 millimoles of KOH to
give 25.0 millimoles of water.
Total
volume of the solution = 25.0 mL + 25.0 mL = 50.0 mL.
Density
of water is 1 g/mL. Use this to calculate the mass of the solution.
<span>Mass
of the solution – 50.0 mL x 1 g/mL = 50.0
</span>
The
specific heat of water is 4.184 J/gK. The temperature of the solution is
increased from 23.5 degrees Celsius to 30.17 degrees Celsius.
The
amount of heat released = 4.184 J/gK x 50.0 g x (30.17C – 23.50C) 1395 J
The
amount of heat released per one mole of water formed can be calculated as shown
:
The
amount of heat released for formation of mole water = 1395 J / (25.0 m mol x
1mol/1000 m mol)
=
55,800 J
<span> </span>
Answer:
The answer to your question is HCl + NaOH ⇒ NaCl + H₂O
Explanation:
Data
Double displacement reaction
Balanced chemical reaction
HCl + NaOH ⇒ NaCl + H₂O
Reactants Elements Products
1 Chlorine (Cl) 1
1 Sodium (Na) 1
2 Hydrogen (H) 2
1 Oxygen (0) 1
As we can see, the reaction is balanced and the coefficients of all reactants and products are 1, but the number is not written in a balanced reaction.
