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3 years ago

.................................

Mathematics

1 answer:

horsena [70]3 years ago

5 0

We know:
$a^{-n}=\dfrac{1}{a^n}$
therefore
$2a^{-4}m^5=2\cdot\dfrac{1}{a^4}\cdot m^5=\dfrac{2m^5}{a^4}$
Answer: B 2m^5/a^4

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Which property explains how we get the equation shown in step 2? Given: -5(x -4) - 20 = -15 Step 1: -5x + 20 -20 = -15 (Distribu

Talja [164]

Step 2: <span>Inverse Property of Addition
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answer
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irina [24]

Answer:

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2 years ago

1. if csc β = 7/3 and cot β = - 2√10 / 3, Find sec β

slava [35]

Step-by-step explanation:

$\tan \beta = \frac{1}{ \cot \beta } = - \frac{3}{2 \sqrt{10} } = - \frac{3 \sqrt{10} }{20}$

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Use the identity

$\cos y = \sqrt{1 - \sin ^{2} y} \: \: \: \: \: \: \: \: \: \: \: \\ = \sqrt{1 - {( - \frac{ \sqrt{6} }{3}) }^{2} } = - \frac{ \sqrt{3} }{3}$

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

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3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,

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Solving for tan x:

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3 years ago

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adell [148]

Answer:

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