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3 years ago

.................................

Mathematics

1 answer:

horsena [70]3 years ago

5 0

We know:
$a^{-n}=\dfrac{1}{a^n}$
therefore
$2a^{-4}m^5=2\cdot\dfrac{1}{a^4}\cdot m^5=\dfrac{2m^5}{a^4}$
Answer: B 2m^5/a^4

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Answer:

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(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

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Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

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On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

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