3 years ago

.................................

1 answer:

5 0

We know:
$a^{-n}=\dfrac{1}{a^n}$
therefore
$2a^{-4}m^5=2\cdot\dfrac{1}{a^4}\cdot m^5=\dfrac{2m^5}{a^4}$
Answer: B 2m^5/a^4

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