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4vir4ik [10]
3 years ago
10

Pls help will give brainliest

Mathematics
1 answer:
spayn [35]3 years ago
6 0

Answer:

7

Step-by-step explanation:

Let the width of the mechanical pencil lead be w_m and the width of a human hair be w_h. We are trying to find the number of widths of pieces of hair (let that be n) that make it equal to the width of a mechanical pencil lead, so we write the equation w_m=n*w_h. Hopefully, writing an equation makes this easier to understand!

Now, I want n, so I divide be w_h on both sides, substitute, and get that n = w_m/w_h = (7*10^-4)/(1*10^-4)

The 10^-4’s cancel, so we get n = 7/1 = 7.

I hope this helps! :)

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Jane has 6/7 of a yard of ribbon. She uses 3/4 of a yard to trim an ornament. how much ribbon is left?
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Answer:

2/28

Step-by-step explanation:

3 0
3 years ago
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8k^4 -3k^2 multiplied by 5k^2
S_A_V [24]

Answer: 40k⁶-15k⁴

Step-by-step explanation:

(8k^4-3k^2)(5k^2)=\\\\8k^4(5k^2)-3k^2(5k^2)=\\\\8(5)(k^{4+2})-3(5)(k^{2+2})=\\\\40k^6-15k^4

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Carmen deposited $6,000 into a savings account that earns 2.8% interest compounded annually. How much will she have in her accou
Anna [14]

To help Carmen find the total after 3 years

We'll have to use the annual compound interest formula: A = P(1 + r)ⁿ

A = Final balance (?)

P = Principal balance (6000)

r = Rate (0.028)

n = years (3)

A = 6000(1 + 0.028)³

A = 6000(1.028)³

A = 6000(1.086373952)

A = 6518.243712

Round that to the nearest cent, and we get $<u>6,518.24 </u>as the answer.

6 0
2 years ago
Number 6 plz help plz
goldenfox [79]
Pat attention to the ending of the numbers. If there are an odd amount of odds, it's going to be odd. If there is an even amount of odds, it's going to be even. If there's only evens, it's only going to stay even.
6 0
3 years ago
The graphs of the function f (given in blue) and g (given in red) are plotted above. Suppose that u(x)=f(x)g(x) and v(x)=f(x)/g(
Rus_ich [418]
U(x) = f(x).(gx)
v(x) = f(x) /  g(x)

Use chain rule to find u(x) and v(x).

u '(x) = f '(x) g(x) + f(x) g'(x)

v ' (x) = [f '(x) g(x) - f(x) g(x)] / [g(x)]^2

The functions given are piecewise.

You need to use the pieces that include the point x = 1.

You can calculate f '(x) and g '(x) at x =1, as the slopes of the lines that define each function.

And the slopes can be calculated graphycally as run / rise of each graph, around the given point.

f '(x) = slope of f (x); at x = 1, f '(1) = run / rise = 1/1 = 1

g '(x) = slope of g(x); at x = 1, g '(1) = run / rise = 1.5/ 1 = 1.5

You also need f (1) = 1 and g(1) = 2

Then:

u '(1) =  f '(1) g(1) + f(1) g'(1) = 1*2 + 1*1.5 = 2 + 1.5 = 3.5

v ' (x) = [f '(1) g(1) - f(1) g(1)] / [g(1)]^2 = [1*2 -  1*1.5] / (2)^2 = [2-1.5]/4 =

= 0.5/4 = 0.125

Answers:
u '(1) = 3.5
v '(1) = 0.125

 


 

3 0
3 years ago
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