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drek231 [11]
3 years ago
7

Ng Order of Operations George has $15. He would like to know if he has enough money to see a movie ($9.00) and buy a pretzel ($2

.65), a drink ($1.35), and two veggie cups ($1.74 each). George incorrectly used this numerical expression to decide if he had enough money. 15 - 9 + 2.65 + 1.35 + 2(1.74) Use the order of operations to simplify this expression.
Mathematics
1 answer:
UNO [17]3 years ago
5 0

Answer:

No, George does not have enough money to buy everything.

The correct expression is:

15 - 9 - 2.65 - 1.35 - 2(1.74)

Step-by-step explanation:

Given that:

Money present with George initially = $15

Money required to see the movie = $9

Money required to buy a pretzel = $2.65

Money required to buy a drink = $1.35

Money required to buy 2 veggie cups = $2(1.74)

To find:

Whether there is enough money with George to complete all the tasks.

Solution:

First of all, let us calculate all the money required and then we can subtract all the money from the initial amount to find whether there is enough money present with George.

If the result is in positive, there is enough money with George.

Total money required for all the activities = $9 + $2.65 + $1.35 + $2(1.74) = $16.48

Expression = $15 - $16.48 = -$1.48

The result is negative, therefore there is not enough money.

The correct expression is:

15 - 9 - 2.65 - 1.35 - 2(1.74)

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Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

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Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

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Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

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