Let us say T= probability of head turning up = 1/2 in one toss
H = probability of a tail turning up = 1/2 in one toss
Then P (56 heads or more) =
1/2^100 [ C(100,56) + C(100,57) + C(100,58) + ....
C(100,98) + C(100,99) + C(100,100) ]
where C(N, R) = N ! / [ (N - R)! R! ] number of occurrances of R formed from
N tosses.
It is 6 just look at the x
Answer:
y = 9 + 4x/3
x = -27/4 + 3y/4
*everything that looks like x/y is a fraction, -27/4 is entirely negative
Woah! Those are some big numbers! Anyways heres my answer: I used the old school way of fuigreing this out but using the pencil and paper I fuigred out 546463+54543 is equal to 601006 and if you were to multiply this by 64 (it took a LONG time for me and quite a few mess ups) its 38464384. Though I gave you the answer I'm just wondering if you could use a calculator because it would be a whole lot easier if you were able to do so.
