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4 years ago

Each molecule of table sugar, C12H22O11, contains

Chemistry

2 answers:

algol [13]4 years ago

7 0

Answer : The correct option is, (d) 12 atoms of carbon.

Explanation:

The formula of given molecule of table sugar is, $C_{12}H_{22}O_{11}$

The given molecule is made up of three elements which are, carbon, hydrogen and oxygen.

In the given molecule of table sugar $C_{12}H_{22}O_{11}$ , there are 12 number of carbon atoms, 22 number of hydrogen atoms and 11 number of oxygen atoms.

From the given options we conclude that, the option (d) is the correct option. While the other options are incorrect.

Hence, the correct option is, (d) 12 atoms of carbon.

Delicious77 [7]4 years ago

3 0

D, because C12 means there's 12 atoms of carbon.

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Answer:

$m_{P_2Cl_5 }=239.2125gP_2Cl_5$

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$m_{P_2Cl_5 }=2.00molP*\frac{2molP_2Cl_5}{4molP} *\frac{239.2125gP_2Cl_5 }{1molP_2Cl_5} \\\\m_{P_2Cl_5 }=239.2125gP_2Cl_5$

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4 years ago

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3 years ago

Describe, in detail, to a freshman undergraduate how to make 1 liter of LB + Kan (100 μg/ml final concentration) + Amp (50 μg /m

mario62 [17]

Answer:

Explanation:

The objective here is to prepare 1 liter of LB + Kan (100 μg/ml final concentration) + Amp (50 μg /ml final concentration) liquid media.

Given that :

the Stock concentration of Amp: 100 mg/ml (since 1 mg/ml = 1000 μg/ml)

it is required that we convert stock concentration in μg/ml since 100 mg/ml = 100000 μg/ml

However, using formula C₁V₁=C₂V₂ (Ampicilin),

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V₂=1000 ml

100000 μg/ml × V₁ = 50 μg/ml × 1000 ml

V₁ = 50 μg/ml × 1000 ml/100000 μg/ml

V₁ = 0.5 ml

Given that:

the Stock concentration of Kan: 25 mg/ml (since 1 mg/ml = 1000 μg/ml)

it is required that we convert stock concentration in μg/ml , 25 mg/ml = 25000 μg/ml

Now by using formula C₁V₁=C₂V₂ (Kanamycin),

C₁ = 25000 μg/ml,

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25000 μg/ml × V₁ = 100 μg/ml × 1000 ml

V₁ = 100 μg/ml × 1000 ml/25000 μg/ml

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