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3 years ago

When more organisms move into an ecosystem and use more resources, the result is

Chemistry

2 answers:

Oxana [17]3 years ago

8 0

The answer would be, "A", "Overpopulation".

Aneli [31]3 years ago

3 0

A) overpopulation :)

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How many moles of cesium xenon heptafloride can be produced from the reaction 12 mol cesium Floride with 14 mol xenon hexaflorid

neonofarm [45]

Answer:

12 moles of cesium xenon heptafluoride

Explanation:

The reaction of cesium fluoride with xenon hexafluoride is CeF + XeF6 -> CeXeF7 and the reaction is balanced as written. So the mole ratio is 1:1:1. We are given 12 moles of CeF and 14 moles of XeF6 are reacting, but after the 12 moles of CeF react completely, the reaction will stop as we have run out of one of our reactants. So only 12 moles of CeXeF7 will be produced.

7 0

2 years ago

A sample of gas is collected in a flask with a volume of 267 mL at a pressure of 771 mmHg and a temperature of 21C. If the mass

nadya68 [22]

Answer:

M=93.5g/mol

Explanation:

I did this in class and it was a review. :)

6 0

2 years ago

Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus

alex41 [277]

Answer: 35.4 g

Explanation:

The balanced reaction is :

$2P+3Cl_2\rightarrow 2PCl_3$

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of phosphorous}=\frac{15.5g}{31g/mol}=0.50moles$

$\text{Moles of phosphorous chloride}=\frac{50.9g}{137g/mol}=0.372moles$

$2P+3Cl_2\rightarrow 2PCl_3$

According to stoichiometry :

2 moles of phosphorous chloride are produced by = 3 moles of $Cl_2$

Thus 0.37 moles of phosphorous chloride are produced by= $\frac{3}{2}\times 0.372=0.558moles$ of $Cl_2$

Mass of $Cl_2=moles\times {\text {Molar mass}}=0.558moles\times 71g/mol=35.4g$

Thus 35.4 g of chlorine reacted with the phosphorus

5 0

2 years ago

Read 2 more answers

[H3O+] of a 3.0 x 10-2 M NaOH<br> soln?

ikadub [295]

Um what do u mean???????

7 0

2 years ago

N2(g) effuses at a rate that is ______ times that of kr(g) under the same conditions.

Bogdan [553]

Answer:- $N_2$ gas effuses at a rate that is 1.73 times that of Kr gas under the same conditions.

Solution:- Rate of effusion of gases is inversely proportional to the square root of the molar mass of the gas. It is known as Graham's law. The formula is written as:

$\frac{r_1}{r_2}=\sqrt{\frac{M_2}{M_1}}$