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mario62 [17]
4 years ago
13

Please help with this question:)

Chemistry
2 answers:
Crazy boy [7]4 years ago
5 0
the answer might be C.2:1
netineya [11]4 years ago
5 0
It’s 2:1

Hope this helps (:
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what mass of aluminium hydroxide is needed to decompose in order to produce 65.0 L of water at STP in stoichiometry?
pishuonlain [190]
Aluminium Hydroxide on decomposition produces Al₂O₃ and Water vapors. 

<span>                               2 Al(OH)</span>₃    →    Al₂O₃  +  3 H₂O


According to equation at STP,

       67.2 L (3 moles) of H₂O is produced by  =  78 g of Al(OH)₃
So,
                65.0 L of H₂O will be produced by  =  X g of Al(OH)₃

Solving for X,
                                 X  =  (65.0 L × 78 g) ÷ 67.2 L

                                 X  =  75.44 g of Al(OH)₂
Result:
           75.44 g of Al(OH)₂ is needed to decompose in order to produce 65.0 L of water at STP in stoichiometry
6 0
3 years ago
Read 2 more answers
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