Answer:
After 4 s of passing through the intersection, the train travels with 57.6 m/s
Solution:
As per the question:
Suppose the distance to the south of the crossing watching the east bound train be x = 70 m
Also, the east bound travels as a function of time and can be given as:
y(t) = 60t
Now,
To calculate the speed, z(t) of the train as it passes through the intersection:
Since, the road cross at right angles, thus by Pythagoras theorem:
Now, differentiate the above eqn w.r.t 't':
For t = 4 s:
Practically yes
So
If mass is more output may come less so it affects the efficiency practically
But thepritically it doesn't
Answer:
A. -30 N
Explanation:
not sure but if the box isn't moving then the force opposite of Polly would be equal to the force she's exerting.
Answer:
300 miles per hour
Explanation:
Speed is distance per unit time, expressed as s=d/t where t is the time taken, d is distance covered and s is the speed.
Convering s to hrs
To convert seconds to hours, we knkw that 1 hour has 60 minutes and each minute has 60 seconds. Therefore, 1 hour has 60*60=3600 seconds
If 3600s=1 h
60 s=?
By cross multiplication 60s*1 h/3600s=1/60 hours
Given distance as 5 miles and time as 1/60 hours then the speed will be 5 divided by 1/60 hrs which is equivalent to 5*60=300 miles per hour
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