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34kurt
3 years ago
9

Type of energy transformed into chemical energy by plants is called type of energy transformed into chemical energy by plants is

called @Physics
Physics
1 answer:
yuradex [85]3 years ago
6 0
I think the correct answer is light energy. It is light energy that is transformed into chemical energy by plants by the process called photosynthesis. In this process, plants<span> take in water, carbon dioxide, and sunlight and </span>turn<span> them </span>into<span> glucose and oxygen.</span>
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What is the magnitude of a vector that has the following components: x = 32 m y = -59 m
maw [93]

Answer:

Can you give me a better explantion

Explanation:

3 0
3 years ago
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A ray of monochromatic light ( f = 5.09 × 10^14 Hz) passes from air into Lucite at an angle
harina [27]
     Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}
 
     Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75
  
     Using the arcsin properties, we get:

sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.

6 0
3 years ago
Sophie applies a 50 n force to push a box 2 meter across the floor calculate the smount of work done in the box
kicyunya [14]
Work done = force x distance

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4 0
3 years ago
According to Newton's Universal Law of Gravitation, when the distance between two interacting objects doubles, the gravitational
maksim [4K]

Answer:

<em>If the distance doubles, the gravitational force is divided by 4</em>

Explanation:

<u>Newton’s Universal Law of Gravitation </u>

Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.

\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}

Where:

m1 = mass of object 1

m2 = mass of object 2

r     = distance between the objects' center of masses

G   = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2

If the distance between the interacting objects doubles to 2r, the new force F' is:

\displaystyle F'=G{\frac {m_{1}m_{2}}{(2r)^{2}}}

Operating:

\displaystyle F'=\frac{1}{4}G{\frac {m_{1}m_{2}}{r^{2}}}

Substituting the original value of F:

\displaystyle F'=\frac{1}{4}F

If the distance doubles, the gravitational force is divided by 4

5 0
3 years ago
A scientist makes a device to catch baseballs. A long bar of total mass 2.2kg and length 1.2m is fixed at its center. It catches
Valentin [98]

Answer:

ωf = 4.53 rad/s

Explanation:

By conservation of the angular momentum:

Ib*ωb = (Ib + Ic)*ωf

Where

Ib is the inertia of the ball

ωb is the initial angular velocity of the ball

Ic is the inertia of the catcher

ωf is the final angular velocity of the system

We need to calculate first Ib, Ic, ωb:

Ib = mb*(L/2)^2=0.15*(1.2/2)^2=0.054 kg.m^2

Ic = mc/12*L^2=2.2/12*1.2^2=0.264 kg.m^2

ωb = Vb / (L/2) = 16 / (1.2/2) = 26.67 m/s

Now, ωf will be:

\omega f = \frac{Ib*\omega b}{Ib + Ic}  = 4.53rad/s

8 0
3 years ago
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