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Vadim26 [7]
3 years ago
13

A basketball player jumps straight upward. After 0,625 s, she is 0.441 m above the ground. What is her initial velocity?????????

Physics
1 answer:
Lunna [17]3 years ago
4 0

Answer:

v₀ = 3.77 [m/s]

Explanation:

This problem can be solved in a simple way by means of the following equation of kinematics.

y=y_{o}+v_{o}*t+\frac{1}{2}*g*t^{2}

where:

y - yo = 0.441 [m]

Vo = initial velocity [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 0.625 [s]

0.441 = v_{o}*(0.625)-\frac{1}{2} *9.81*(0.625)^{2} \\2.357 = v_{o}*0.625\\v_{o}=3.77[m/s]

Note: The sign of the acceleration is negative since the movement of the basketball player is against of the gravity acceleration.

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Answer:

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Explanation:

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that why here

|v(1)| = |v(2)| = 3/5 c        ......................2

and

γ = 1 / √(1 − v²/c²)           .......................3

put here v = 3 and c is 5

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γ =  5/4

so

γ(1) = γ(2) = γ = 5/4  

so from equation 1

γ(1)m(1)c² + γ(2)m(2)c²  = Mc²

M = 2γm0

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7 0
4 years ago
After Moseley's discovery in 1913, the periodic law stated that physical and chemical properties tend to repeat periodically whe
stich3 [128]

Answer:

Option B

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The correct answer is Option B.

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3 0
3 years ago
HELP!!!
nekit [7.7K]
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6 0
3 years ago
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Which of these is one way that mechanical waves differ from electromagnetic waves?
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To measure moderately low pressures, oil with a density of 9.0 x 102 kg/m3 is used in place of mercury in a barometer. A change
Yuki888 [10]

Answer:

Δ P =  13.24 Pa

Explanation:

Given that

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3 0
4 years ago
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