To solve this problem we will apply the two concepts mentioned. To find the constant we will apply Hooke's law, and to find the period we will apply the relationship between the mass and the spring constant. Let us begin,
PART A) For this section we will use Hooke's law. In turn, since the force applied is equivalent to weight, we will use Newton's law for which weight is defined as the product between mass and gravity. This weight is equal to the Spring Force.
Here,
k = Spring constant
= Displacement
F = Force, the same as the Weight (mg)
Then we have that
Therefore the spring constant is 13.23N/m
PART B) To find the period of oscillation, the relationship that allows us to find is given by the following mathematical function,
Here
m = mass
k = Spring constant
Replacing,
Therefore the period of the oscillation is 0.491s
Answer:
A
Explanation:
A virtual image is on the same side as the object, which by convention is drawn on the left side. So -di would represent a virtual image.
Answer:
10^-7 C
Explanation:
m = 1 g = 10^-3 kg, E = 200,000 N/C, a = 20 m/s^2, u = 0
Let q be the charge on bead
Force = m a = q E
a = q E / m
q = m a / E = (10^-3 x 20) / 200000 = 10^-7 C
Given the values to proceed to solve the exercise, we resort to the solution of the exercise through differential equations.
The problem can be modeled through a linear equation, in the form:
With the initial conditions as,
Where Q(t) is the charge.
<em>The general solution of a linear equation is given as:</em>
<em>
</em>
Applying this definiton in our differential equation we have that
To find b and a we use the first equation and find the roots:
Then we have
To find the values of the Constant we apply the initial conditions, then
And for the derivate:
We have a system of 2x2:
Solving we have:
The we can replace at the equation and we have that the Charge at any moment is given by,
If we obtain the derivate we find also the Current, then
The arrangements of the water molecules they begin to spread apart. As the water(ice) melts the molecules develop fewer compact and start juddering harder until the ice has changed state into liquid.
