1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Varvara68 [4.7K]
3 years ago
14

A force of 20 N is exerted on a box with a mass of 15 kg. if friction exerts a force of 4 N on the box, at what rate does the bo

x accelerate?
Physics
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

1.06 metres per second squared

Explanation:

since friction acts against foward force

20 N - 4 N = 16 N

use Newtons 2nd law F=ma Solve for a:

a= F÷m

= 16 ÷ 15

= 1.06 metres per second squared

You might be interested in
Which form of energy is responsible for the change of state here?
liq [111]

Answer:

d

Explanation:

8 0
3 years ago
Please help It is Anatomy and Phys
kap26 [50]

Answer:

the last time i had my tempature taken was at disney prings about a week ago -_- they used one of those gun things that dont touch u and the SHOVED me forward so i guess i was fine

Explanation:

3 0
3 years ago
Read 2 more answers
What is the amount of force required to accelerate a 20 kg object to 5 m/s˛?
Llana [10]

Answer:

Force = 100N

Explanation:

Force = mass  × acceleration

3 0
3 years ago
A roller skater of 47kg moving with a velocity of 12 m/s to the east picks up a bag of 6.0 kg. What is the final velocity of the
WITCHER [35]

Answer:

v_f = 10.85 m/s

Explanation:

We will apply the law of conservation of momentum here:

m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f}+m_{2}v_{2f}\\

where,

m₁ = mass of roller skater = 47 kg

m₂ = mass of bag = 6 kg

v_1i = initial speed of roller skater = 12 m/s

v_2i = initial speed of the bag = 0 m/s

v_1f = final speed of the roller skater = ?

v_2f = final speed of the bag = ?

Both the bag and the skater will have same speed at the end because kater is carrying the bag:

v_1f = v_2f = v_f

Therefore, the equation will become:

(47\ kg)(12\ m/s)+(6\ kg)(0\ m/s)=(47\ kg)(v_{f})+(5\ kg)(v_{f})\\564\ N.s = (47\ kg+5\ kg)(v_{f})\\v_{f} = \frac{564\ N.s}{52\ kg}\\

<u>v_f = 10.85 m/s</u>

8 0
3 years ago
Suppose the earth suddenly came to halt and ceased revolving around the sun. The gravitational force would then pull it directly
AleksAgata [21]

Answer:

613373.65233 m/s

Explanation:

M = Mass of Sun = 1.989\times 10^{30}\ kg

m = Mass of Earth

v = Velocity of Earth

r = Distance between Earth and Sun = 147.12\times 10^{9}\ m

r_e = Radius of Earth = 6.371\times 10^6\ m

r_s = Radius of Sun = 695.51\times 10^6\ m

In this system it is assumed that the potential and kinetic energies are conserved

\dfrac{1}{2}Mv_2-\dfrac{GMm}{r_e+r_s}=0-\dfrac{GMm}{r}\\\Rightarrow v=\sqrt{2GM(\dfrac{1}{r_e+r_s}-\dfrac{1}{r})}\\\Rightarrow v=\sqrt{2\times 6.67\times 10^{-11}\times 1.989\times 10^{30}(\dfrac{1}{6.371\times 10^6+695.51\times 10^6}-\dfrac{1}{147.12\times 10^{9}})}\\\Rightarrow v=613373.65233\ m/s

The velocity of Earth would be 613373.65233 m/s

3 0
3 years ago
Other questions:
  • A 150 kg cart is being accelerated by a tractor at a rate of 5 m/s². How much force is the tractor putting on the cart?
    9·1 answer
  • In what direction would the particles in this wave move, relative to the direction of wave travel?
    7·2 answers
  • What would have the greatest gravitational pull on each other?
    6·1 answer
  • A ball is launched at an angle of 39.8 degrees up from the horizontal, with a muzzle velocity of 6.6 meters per second, from a l
    5·1 answer
  • If an object is not moving, what do we know about the forces acting on it?
    11·2 answers
  • Please help!
    7·1 answer
  • It serves as the fuctional unit of the nervous system
    8·2 answers
  • Help REALL FAST PLEASE
    14·1 answer
  • In order for acceleration to occur, something must be..
    14·1 answer
  • Which of the following rays is NOT possible for a converging lens?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!