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Varvara68 [4.7K]
2 years ago
14

A force of 20 N is exerted on a box with a mass of 15 kg. if friction exerts a force of 4 N on the box, at what rate does the bo

x accelerate?
Physics
1 answer:
MakcuM [25]2 years ago
3 0

Answer:

1.06 metres per second squared

Explanation:

since friction acts against foward force

20 N - 4 N = 16 N

use Newtons 2nd law F=ma Solve for a:

a= F÷m

= 16 ÷ 15

= 1.06 metres per second squared

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How much force is needed to accelerate a vehicle with a mass of 1000 kg at a rate<br> of 5 m/s2?
Mashcka [7]
The force needed to accelerate a vehicle with a mass of 1000kg at a rate of 5m/s2 would be 5000
8 0
2 years ago
how much force is needed to move a brick with a mass of 345-kg a distance of 28m while doing 1008 j of work?
Travka [436]

    Work = (force) x (distance)

     1,008 J  =  (force) x (28 m)

Divide each side by 28m  :    (1,008 kg-m²/sec²) / (28 m)  =  force

                                           Force =  36 kg-m/s²  =  36 Newtons .
                                                                      (about 8.1 pounds)

It doesn't matter what that force accomplishes.
It could be moving a brick, lifting a fish, or pushing a little red wagon.
In order to do 1,008 joules of work in 28 meters, it takes 36 N of force,
in the direction of the 28 meters.
5 0
2 years ago
The human body is 65% oxygen by mass. If a person has a mass of 75.0 kg, what is the mass oxygen in his body?
Gekata [30.6K]
65% x 70 = 45.5 
The mass of oxygen in his body is 45.5 kg
4 0
3 years ago
An L-C circuit containing an 82.0-mH inductor and a 1.60-nF capacitor oscillates with a maximum current of 0.800 A . Assuming th
ryzh [129]

Answer:

19.5 mJ

Explanation:

Assuming perfect components without resistance or losses, the circuit should oscillate indefinetly.

The circuit will have a natural pulsation of

w = \frac{1}{\sqrt{L * C}} = \frac{1}{\sqrt{82e-3 * 1.6e-9}} = 87304 rad/s

f = \frac{w}{2\pi} = \frac{87304}{2\pi} = 13895 Hz

T = \frac{1}{f} = \frac{1}{13895} = 7.2 \mu s

So, by the time t = 2.4 ms, 333.33 cycles would have passed

\frac{2.4 ms}{7.2 \mu s} = \frac{2400 \mu s}{7.2 \mu s} = 333.33

Therefore it would be at one third after the beginning of the cycle. The circuit would be in an equivalent state as t = (7.2 us)/3 = 2.4us

At t=0 the capacitor is fully charged, so the voltage is maximum and the current is 0. The current will increase towards a maximum of 800 mA at t=T/4, then decreas to 0 at t=T/2, decrease to -800 mA at 3T/4 and go back to 0 at t=T following a sine wave.

The equation of this sine wave would be

I(t) = I0 * sin(w * t)

I(T/3) = 0.8 * sin(w * T/3)

Since w = 2π/T

w * T = 2π

I(T/3) = 0.8 * sin(2 \pi /3) = 0.8 * 0.866 = 0.69 A

The current stored in an inductor is

E = \frac{1}{2} * L * I^2

E = \frac{1}{2} * 82e-3 * 0.69^2 = 0.0195 J = 19.5 mJ

6 0
3 years ago
Explain in terms of the arrangementbof particles the kinetic theory of matter​
baherus [9]

Answer:

Matter is made up of particles that are constantly moving. All particles have energy, but the energy varies depending on the temperature the sample of matter is in. This in turn determines whether the substance exists in the solid, liquid, or gaseous state.

Explanation:

5 0
2 years ago
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