Answer:
Energy
Explanation:
One ways of stating the law of conservation of energy is that "you cannot get more energy from a machine than the amount of energy you put into it".
The law of conservation of energy states that in a system, energy is neither created nor destroyed but transformed from one form to another.
The energy in a system does not increase based on the premise of this law.
- The efficiency of a machine can reduce but the energy is always conserved.
- This is because energy is transformed to other forms.
Answer:
First law can be deduced from second law.
Acceleration may determine the position and velocity of the system.
Explanation:
When net force is zero, the second law is 0 = ma, or the motion is at constant speed. Thus first law establishes that when there are no forces, the object moves at constant speed, so first law is explained by using the second.
If you determine the acceleration of a system, you may use calculus or kinematic equations to determine velocity and position of the particle and determine how it moves. This is very important in mechanics and engineering, for example, for spacecrafts, forensic situations, etc.
Answer:
230.4 N
Explanation:
From the question given above, the following data were obtained:
Charge (q) of each protons = 1.6×10¯¹⁹ C
Distance apart (r) = 1×10¯¹⁵ m
Force (F) =?
NOTE: Electric constant (K) = 9×10⁹ Nm²/C²
The force exerted can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × (1.6×10¯¹⁹)² / (1×10¯¹⁵)²
F = 9×10⁹ × 2.56×10¯³⁸ / 1×10¯³⁰
F = 2.304×10¯²⁸ / 1×10¯³⁰
F = 230.4 N
Therefore, the force exerted is 230.4 N
To be careful towards what you do.
Answer:
6.4 J
Explanation:
m = mass of the bullet = 10 g = 0.010 kg
v = initial velocity of bullet before collision = 1.8 km/s = 1800 m/s
v' = final velocity of the bullet after collision = 1 km/s = 1000 m/s
M = mass of the block = 5 kg
V = initial velocity of block before collision = 0 m/s
V' = final velocity of the block after collision = ?
Using conservation of momentum
mv + MV = mv' + MV'
(0.010) (1800) + (5) (0) = (0.010) (1000) + (5) V'
V' = 1.6 m/s
Kinetic energy of the block after the collision is given as
KE = (0.5) M V'²
KE = (0.5) (5) (1.6)²
KE = 6.4 J
