Answer:
238.75⁰C .
Explanation:
coefficient of linear thermal expansion of aluminum and steel is 23 x 10⁻⁶ K⁻¹ and 12 x 10⁻⁶ K⁻¹ respectively .
Rise in temperature be Δ t .
Formula for linear expansion due to heat is as follows
l = l₀ ( 1 + α x Δt )
l is expanded length , l₀ is initial length , α is coefficient of linear expansion and Δt is increase in temperature .
For aluminum
l = 2.5 ( 1 + 23 x 10⁻⁶ Δt )
For steel
l = 2.506 ( 1 + 12 x 10⁻⁶ Δt )
Given ,
2.5 ( 1 + 23 x 10⁻⁶ Δt ) = 2.506 ( 1 + 12 x 10⁻⁶ Δt )
1 + 23 x 10⁻⁶ Δt = 1.0024 ( 1 + 12 x 10⁻⁶ Δt )
1 + 23 x 10⁻⁶ Δt = 1.0024 + 12.0288 x 10⁻⁶ Δt
10.9712 x 10⁻⁶ Δt = .0024
Δt = 218.75
Initial temperature = 20⁰C
final temperature = 218.75 + 20 = 238.75⁰C .
Answer:
Final velocity will be 556.8 m/sec
Explanation:
We have given the average rate of change of velocity that is
Time
Initial velocity of bullet will be zero that is u=0
Now according to first law of motion
v=u+at, here v is final velocity, u is initial velocity and t is time
So
A. 0.25 terabytes
b. 2.5e + 17
Are you asking us what we think of the universe? lol
The time it takes the Polonium-194 to decay to 1/16 of its original amount is 2.8 seconds.
<h3>What is half-life?</h3>
half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay
To calculate the time it takes the sample of Polonium-196 to decay to 1/16 of its original amount, we use the formula below
Formula:
- = R/R'......... Equation 1
Where:
- n = Total number of time it takes Polonium-194 to decay to 1/16 of its original amount
- t = Half-life of Polonium-194
- R = Original amount of Polonium-194
- R' = Amount of Polonium-194 after decay
From the question,
Given:
Substitute these values into equation 1 and solve for n
Equating the base,
- n/0.7 = 4
- n = 0.7×4
- n = 2.8 seconds.
Hence, the time it takes the Polonium-194 to decay is 2.8 seconds.
Learn more about half-life here: brainly.com/question/25750315
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