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2 years ago

Solve x2-4x-7=0 by completing the square

Mathematics

2 answers:

aleksklad [387]2 years ago

8 0

HEY mate here is pratyush from India for your help...

the answer is with the attachment

hope it helps you..

tatyana61 [14]2 years ago

7 0

Answer:

x = 2 ± $\sqrt11}$

Step-by-step explanation:

Given

x² - 4x - 7 = 0 ( add 7 to both sides )

x² - 4x = 7

To complete the square

add (half the coefficient of the x- term)² to both sides

x² + 2(- 2)x + (- 2)² = 7 + (- 2)²

(x - 2)² = 7 + 4 = 11 ( take the square root of both sides )

x - 2 = ± $\sqrt{11}$ ( add 2 to both sides )

x = 2 ± $\sqrt{11}$ ← exact solutions

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2 years ago

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<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the expression:

$(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} \\\\This\ can\ be\ simplified\ to:\\\\(\frac{2(2k+1)(k-2)}{(k+2)(k-2)(2k+1)}) \\\\=\frac{2}{k+2}$

The product of the expression $(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1}$ is the expression $\frac{2}{k+2}$

Find out more on equation at: brainly.com/question/2972832

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2 years ago

Solve x2-4x-7=0 by completing the square ​

Solve x2-4x-7=0 by completing the square