Answer:
Explanation:
we know that 1 km =1000 m and 1 hour =60 min
therefore
239 km/hr =239*1000m/60 min=3983.3 m/min
The answer would be Thymine.
Hope this helps! (:
Molar mass KOH = 56.11 g/mol
Molarity = 1.50 M
Volume = 2.50 L
m = molarity x molar mass x volume
m = 1.50 x 56.11 x 2.50
m = 210.4125 g
hope this helps!
Answer: 25.89g of O2 (g)
Explanation:
We begin by finding the molar mass of compounds of interest in the given equation. 2 KClO3 ⟶ 2 KCl + 3 O 2
1 mole of KCLO3 = 39 .10 + 35.5 + (3x16) = 122.55g, 2Moles would be 2 x 122.5 = 245.1g
1 mole Oxygen gas = 32g, 3 moles would be, 3 x 32= 96g
According to the equation;
245.1g of KCLO3 produces 96g of O2 (g)
If 1g of KCLO3 produces 96÷245.1 of O2 (g) from heating.
66.1g of KCLO3 would produce; 96÷245.1 x 66.1 = 25.89g of O2 (g) from heating.