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KatRina [158]
3 years ago
12

2FeCl3 ---> 2FeCl2 + Cl2

Chemistry
2 answers:
vesna_86 [32]3 years ago
8 0
The correct options are as follows: 
1. In the chemical equation given above, Fe3+  IS REDUCED.
A reduction is a process in which an atom of an element gains an electron and therefore become reduced. In this type of reaction, the positive character of the atom is reduced. Looking at the equation given above, you will notice that, the positive character of Iron is reduced form +3 to +2.

2. In the reaction given above, the chlorine atom is OXIDIZED.
An oxidation is a process in which an atom loses an electron, thereby increasing its oxidation number. In this case, the positive character of the atom is increased. Looking at the chlorine atom given above, you will notice that it has a charge of -1 before and now it has change to neutral, which means that, it has given out the electron it gains earlier.

3. This type of redox reaction can not take place. This is because, in chemical reaction, the chlorine atom is always looking for another element that will donate an electron to it in order to become stable. Thus, chlorine atom easily gain electrons but it can not donate an electron to another element.<span />
Taya2010 [7]3 years ago
7 0

Answer:

Reduced

Oxidized

No

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Octane has a density of 0.692 g/ml at 20°C. Grams of O₂ required to burn 15.0 gal of C₈H₁₈ is 1.37868×10⁵g.

Octane is a hydrocarbon having eight carbon atoms and have single bonds only.

Given,

Density of octane = 0.692g/ml

Temperature = 20°C = 293K

Amount of Octane present = 15gal

Molar mass of octane = 114g

We know that,

1 gal = 3.78541L = 3785.4ml

Hence, 15 gal = 56781 ml

Now let's calculate the Mass of octane required:

Mass of octane = 0.692 x 56781

Mass of octane = 39292.45 g

According to the given equation,

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Also, 114g of octane needs-------> 400g of oxygen

39292.45g of octane needs ---------> 137868.24g of oxygen

Hence, oxygen needed to burn octane is 1.37868×10⁵g

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