Answer:
double
Explanation:
radius = r
length = l
Surface area, A = 2 π r l .... (1)
Now the radius is doubled = 2r
length is same
Surface area, A' = 2 x π x 2 r x l
A' = 2 x 2πrl
A' = 2 A (from equation (1)
Thus, the surface area is doubled.
Lindsay should fly the plane in the direction [W 12.5° S] to get Hamilton.
Using Sine rule to solve this question
Sine rule => SinA/a = SinB/b = SinC/c = constant
The magnitude of wind is 50 with an angle of 60 degrees.
The magnitude of plane is 200 and the angle at which it should fly is unknown and should be θ.
One side is 50 km/hr at an angle of 60 degrees.
sin 60°/200 = sin θ / 50
50 × sin 60° = 200 × sin θ
√3/2 = 4 × sin θ
√3/8 = sin θ
sin θ = 0.2165
θ = sin⁻¹(0.2165)
θ = 12.5°
So Lindsay have to fly the plane in the direction of [W 12.5° S].
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Answer:
Liquid
Explanation:
To turn liquid into gas, you add heat, to remove heat from gas, you make liquid.
The net force on the -4.0μC object as a result of this net field will be -10.4 N.
<h3>What is the charge?</h3>
The matter has an electric charge when it is exposed to an electromagnetic field is known as a charge.
The electric field intensity is found as the force per unit charge.
Electric field intensity on the positive charge:

Electric field intensity on the negative charge:

The net charge is the algebraic sum of the two charges;

Hence, as a result of this net field, the net force on the -4.0C object will be -10.4 N.
To learn more about the charge refer to the link;
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Answer:
1.28 m
Explanation:
Given;
Radius, r = 1.5 cm = 0.015 m
Time, t = 19 s
Average angular speed = 4.5 rad/s
Consider a point when the tape is moving at a constant velocity along the circumference of the circular reel of radius r. The linear velocity v at this point is given by;
v = rω ----(1)
Where
v is the linear velocity of the circular motion
r is the radius of the reel
ω is the the angular velocity.
At a point the tap undergoes a linear motion before passing round the reel of the cassette. The linear velocity v at this point is given by;
v = L/t ----(2)
where;
v is the velocity of the linear motion
L is the length of the tape (distance covered by the tape)
t is the time taken
Equating equation(1) and equation (2)
L/t = rω
L = rωt
Substituting the given values,
L = 0.015 × 4.5 × 19
L = 1.2825 m
L = 1.28 m