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uysha [10]
3 years ago
12

if you have a aluminum alloy rodthat has a cross- sectional area of 1.35 in. squared. what is the maximum tensile force that can

be applied along the axis​
Physics
1 answer:
Gekata [30.6K]3 years ago
3 0

Answer:

Explanation:

where ΔL is the amount of deformation (the change in length, for example) produced by the force F, and k is a proportionality constant that depends on the shape and composition of the object and the direction of the force. Note that this force is a function of the deformation ΔL—it is not constant as a kinetic friction force is. Rearranging this to

We now move from consideration of forces that affect the motion of an object (such as friction and drag) to those that affect an object’s shape. If a bulldozer pushes a car into a wall, the car will not move but it will noticeably change shape. A change in shape due to the application of a force is a deformation. Even very small forces are known to cause some deformation. For small deformations, two important characteristics are observed. First, the object returns to its original shape when the force is removed—that is, the deformation is elastic for small deformations. Second, the size of the deformation is proportional to the force—that is, for small deformations, Hooke’s law is obeyed. In equation form, Hooke’s law is given by

makes it clear that the deformation is proportional to the applied force. Figure 1 shows the Hooke’s law relationship between the extension ΔL of a spring or of a human bone. For metals or springs, the straight line region in which Hooke’s law pertains is much larger. Bones are brittle and the elastic region is small and the fracture abrupt. Eventually a large enough stress to the material will cause it to break or fracture.

ΔL=

​k

​

​F

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6 0
3 years ago
A 4-kg block and a 2-kg block can move on the horizontal frictionless surface. The blocks are accelerated by a+12-N force that p
lozanna [386]

Answer:

F_n = -4 N

Explanation:

Net external force that exerted on the block is given as

F_{net} = (m_1 + m_2) a

here we know that

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now we have

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so we have

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now the force exerted by bigger block on smaller block is given as

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You are working at a company that manufactures electrical wire. Gold is the most ductile of all metals: it can be stretched into
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Answer:R=1.424 M\Omega

Explanation:

Given

mass of gold m=1.6 gm

Length of wire L=2.2 km

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density of gold =19.3\times 10^3 kg/m^3

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And Resistance R=\frac{\rho L}{A}

also be written as

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where L=length

V=volume

\rho =resistivity\ of\ gold

R=\frac{2.44\times 10^{-8}\times (2200)^2}{8.29 \times 10^{-8}}

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R=1.424 M\Omega

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