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salantis [7]
2 years ago
14

Fill in the blank the process of evaporative cooling helps the body .

Physics
1 answer:
Nina [5.8K]2 years ago
3 0

Answer:

The process of evaporative cooling helps the body is explained below in complete details.

Explanation:

Your body performs the application of the evaporative process when secreting. Sweat, which contains 90 percent water, commences evaporating. ... This appears in a cooling impression (described as evaporative cooling) that serves to sustain body temperature and cools the body down when it becomes too hot.

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How should ready-to-eat food be stored after it has cooled?
snow_lady [41]

Answer:

The answer is most likely C.

Ready-to-eat foods are stored at the top of the fridge, away from raw foods so that harmful bacteria cannot transfer from the raw food to the cooked food. Raw meat, poultry and fish in sealed containers to stop them touching or dripping onto other foods.

5 0
3 years ago
If the particles of an object have more kinetic energy than the particles of an object, what must be true?
son4ous [18]

If the objects comprise a gas, then the first object contains more
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7 0
3 years ago
A parallel-plate air capacitor is made from two plates 0.190 m square, spaced 0.770 cm apart. It is connected to a 120 V battery
Naddik [55]

Answer:

aaksj

Explanation:

a) the capacitance is given of a plate capacitor is given by:

C = \epsilon_0*(A/d)

Where \epsilon_0 is a constant that represents the insulator between the plates (in this case air, \epsilon_0 = 8.84*10^(-12) F/m), A is the plate's area and d is the distance between the plates. So we have:

The plates are squares so their area is given by:

A = L^2 = 0.19^2 = 0.0361 m^2

C = 8.84*10^(-12)*(0.0361/0.0077) = 8.84*10^(-12) * 4.6883 = 41.444*10^(-12) F

b) The charge on the plates is given by the product of the capacitance by the voltage applied to it:

Q = C*V = 41.444*10^(-12)*120 = 4973.361 * 10^(-12) C = 4.973 * 10^(-9) C

c) The electric field on a capacitor is given by:

E = Q/(A*\epsilon_0) = [4.973*10^(-9)]/[0.0361*8.84*10^(-12)]

E = [4.973*10^(-9)]/[0.3191*10^(-12)] = 15.58*10^(3) V/m

d) The energy stored on the capacitor is given by:

W = 0.5*(C*V^2) = 0.5*[41.444*10^(-12) * (120)^2] = 298396.8*10^(-12) = 0.298 * 10 ^6 J

6 0
3 years ago
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How can accuracy be limited?
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Answer:

accuracy refers to the deviation of a measurement from a standard or true value of the quantity being measured

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