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melomori [17]
3 years ago
11

Will give BRAINLIEST!! Write a polynomial and show all the steps you would take to factor this polynomial completely. Please exp

lain each step thoroughly.
I am not accepting links. Thank you:)
Mathematics
1 answer:
Nikolay [14]3 years ago
3 0

Step-by-step explanation:

Consider this polynomial,

8 {x}^{2}  + 2x - 3

First, I do the AC memethod. To find my two numbers,

That is to find two numbers that multiplied will equal my leading coeffeicent, A times my constant, C

And that will also add to 2, my middle term.

So using that

8 \times  - 3 =  - 24

So let find factors of-24:

Factors can be positve or negative

The factors of 24 are : 1,2,3,4,6 8,12,24.

So which one of these add up to 2.

6 + ( - 4) = 2

and

6 \times  - 4 =  - 24

So six and negative four is our numbers.

Now, let set up our binomials

Step 1: Rewrite the orginal equation by using 6x and -4x instead of 2x.

Disclaimer: The placement of these numbers doesn't matter.

So we have

8 {x}^{2}  + 6x - 4x - 3

Step 2: Group the first two terms and last two terms

(8 {x}^{2}  + 6x) + ( - 4x - 3)

Factors the first group by finding the GCF.

x is the greatest common variable, and 2 is the gcf so we have

2x(4x + 3) + ( - 4x - 3)

Next, factor the next group by -1.

2x(4x + 3) - 1(4x  + 3)

Combine the outside factors.

(2x - 1)(4x + 3)

So those are the factors.

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4 years ago
A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi
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Answer:

Side length = \sqrt{\frac{A}{3} } cm ,   Height =  \frac{1}{2} \sqrt{\frac{A}{3} } cm  ,  Volume = \frac{A\sqrt{A}}{6\sqrt{3} }  cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

  1. y = \frac{A - x^{2} }{4x}

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( \frac{A - x^{2} }{4x} )

V =  \frac{Ax - x^{3} }{4}

To find max volume put V' = 0

So taking derivative equation becomes

\frac{A - 3 x^{2} }{4} = 0

A = 3 x^{2}

x^{2} = \frac{A}{3}

x = \sqrt{\frac{A}{3\\} }

put value of x in equation 1

y = \frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }  

y = \frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }

y = \frac{1}{2} \sqrt{\frac{A}{3} }

So the volume will be

V = x^{2} × y

Put values of x and y from equation 2 & 3

V = \frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )

V = \frac{A\sqrt{A}}{6\sqrt{3} }

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Answer:

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