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ASHA 777 [7]
4 years ago
9

In a free fall experimate you determine the value of acceleration due to gravity (g) to be 9.50 m/s2 . The accepted value is 9.8

1 m/s2 . What your percent error?
Physics
1 answer:
lisov135 [29]4 years ago
3 0

If the value 9.81 is correct, then your error is (-0.31).

As a fraction of the correct value, your error is  (-0.31)/(9.81) .

That's -0.0316,  or  -3.16 percent .

By the way ... LAST time somebody posted this same question on Brainly, he was nice enough to also let us see the list of choices.

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The velocity time graph of a car shown below a) Calculate the magnitude of displacement of the car in 40 seconds. b) During whic
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Answer:

a) 0 metres

b) From time 0 s to 10 s , the car was accelerated. Its velocity accelerated from 0m/s to 20 m/s

c) 20 m/s

Explanation:

a) <em>Formula of displacement= velocity x time</em>

time=40 s

velocity =0 m/s

∴ displacement= 0 x 40 = 0 m

Magnitude of displacement is 0 m

b) The increase in velocity shows that there has been acceleration.

c) The average velocity of the car is =\frac{0+40}{2\\}   {initial velocity + final velocity}

                                                            =\frac{40}{2}

                                                             =20

Therefore, the magnitude of the average velocity  of the car is 20 m/s

3 0
3 years ago
A nuetral atom has no overall charge. Explain this in terms of its particles.
agasfer [191]
Firstly an atom has electrons , protons and neutrons. The protons are positively charged and the electrons are negatively charged and the neurons are neutral. So in a neutral atom the amount of protons equals to the amount of electrons. Thus the protons and neutrons can be called particles
6 0
4 years ago
A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 10 m from the takeoff point. you may want t
Stells [14]

<u>Answer:</u>

Takeoff speed of Kangaroo = 12.91 m/s

<u>Explanation:</u>

  The distance reached by Kangaroo =  10 meter

  Angle at which it jumps = 18°

  The motion of Kangaroo is like a projectile, the distance traveled is the range of projectile.

   Range of projectile = Time taken for the projectile to reach ground* Horizontal velocity

   Time taken for the projectile to reach ground:

       Time taken = Two times of the time taken for the projectile to reach maximum height

       Time taken for the projectile to reach maximum height = Vertical speed / Acceleration = u sin θ/g

      Time taken for the projectile to reach ground = 2 u sin θ/g

  So Range of projectile = ucos\theta*\frac{2usin\theta}{g} =\frac{u^2sin2\theta}{g}

 We have Range = 10 meter, θ = 18⁰

    Substituting

        10=\frac{u^2sin(2*18)}{9.8}\\ \\ u^2= 166.73\\ \\ u=12.91 m/s

 Takeoff speed of Kangaroo = 12.91 m/s

3 0
3 years ago
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Answer:   6.605

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