When an object with a height of 0.10 meter is placed at a distance of 0.20 meter from a convex spherical mirror, the image will
1 answer:
Answer:
0.03 m
Explanation:
Mirrors work on the principle of reflection.
Reflection occurs when a ray of light hits a surface and bounces back into the origina medium at a different angle.
We can solve this problem by using the magnification equation:
where
y' is the size of the image
y is the size of the object
q is the distance of the image from the mirror
p is the distance of the object from the mirror
Here we have:
y = 0.10 m is the height of the object
p = 0.20 m is the distance of the object from the mirror
q = -0.06 m is the distance of the image from the mirror (negative because it appears behind the mirror, so it is a virtual image)
Solving for y', we find the size of the image:
And the positive sign indicates that the image is upright.
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Hi there!
We can use the conservation of angular momentum to solve.
Recall the equation for angular momentum:
We can begin by writing out the scenario as a conservation of angular momentum:
= moment of inertia of the merry-go-round (kgm²)
= angular velocity of merry go round (rad/sec)
= final angular velocity of COMBINED objects (rad/sec)
= moment of inertia of boy (kgm²)
= angular velocity of the boy (rad/sec)
The only value not explicitly given is the moment of inertia of the boy.
Since he stands along the edge of the merry go round:
We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:
Plug in the given values:
Now, we must solve for the boy's moment of inertia:
Use the above equation for conservation of momentum:
Answer:
180 m
Explanation:
The rock follows a free-fall motion - so the vertical distance covered can be found by using the equation
where
g = 10 m/s^2 is the acceleration due to gravity
t = 6.00 s is the time of the fall
Substituting these data, we find the height of the cliff: