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3 years ago

15

When an object with a height of 0.10 meter is placed at a distance of 0.20 meter from a convex spherical mirror, the image will

appear to be 0.06 meter behind the mirror. What’s the height of the image?

1 answer:

goblinko [34]3 years ago

5 0

Answer:

0.03 m

Explanation:

Mirrors work on the principle of reflection.

Reflection occurs when a ray of light hits a surface and bounces back into the origina medium at a different angle.

We can solve this problem by using the magnification equation:

$\frac{y'}{y}=-\frac{q}{p}$

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

y = 0.10 m is the height of the object

p = 0.20 m is the distance of the object from the mirror

q = -0.06 m is the distance of the image from the mirror (negative because it appears behind the mirror, so it is a virtual image)

Solving for y', we find the size of the image:

$y'=-\frac{q}{p}y=-\frac{-0.06}{0.20}(0.10)=0.03 m$

And the positive sign indicates that the image is upright.

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