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-Dominant- [34]
3 years ago
15

Mike Powell holds the record for the long jump of 8.95 m, established in 1991. If he left the ground at an angle of 18.8°, what

was his initial speed (in m/s)?
Physics
1 answer:
maksim [4K]3 years ago
7 0

Answer:

<em>12 m/s</em>

Explanation:

<u>Projectile Motion</u>

It's also known as 2D motion because the movement takes place in both axis x and y. The x-axis motion is at a constant speed since in absence of friction, no external force stops or accelerates the object. The y-axis motion is at variable speed, which is changed by the acceleration of gravity that makes the object to reach a maximum height and then go back to ground level.

The maximum horizontal distance reached (also called Range) is given by

\displaystyle X_m=\frac{V_{o}^2sin2\theta}{g}

Knowing that \theta=18.8^o, X_m=8.95\ m, we solve for Vo

\displaystyle V_o=\sqrt{\frac{gX_m}{sin2\theta}}

\displaystyle V_o=\sqrt{\frac{9.8\cdot 8.95}{sin(2\cdot 18.8^o)}}=12\ m/s

Thus, the initial speed of Mike Powell was 12 m/s

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Answer:

speed of each marble after collision will be 1.728 m/sec

Explanation:

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So mass of other marble m_2=25gram=0.025kg

Second marble is at so v_2=0m/sec

We have to find the velocity of second marble

From momentum conservation we know that

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if the instantaneous current in the circuit is giveen by I=3 sin theta amperes, the rms value of the current will be
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Given that,

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We know that,

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