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enyata [817]
1 year ago
11

Q|C A sinusoidal wave in a string is described by the wave function

Physics
1 answer:
creativ13 [48]1 year ago
4 0

The maximum transverse force on a 1.00cm segment of the string is 0.045N.

The maximum transverse force on the segment,

l=1.00cm=1.00cm×1m/100cm=0.01m is,

F=μla

=(12.0×10^−3kg/m)×(0.01m)×(375m/s^2)

=0.045N

Hence the maximum force is 0.045N

Learn more about transverse force here:

brainly.com/question/13618693

#SPJ4

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Newtons second law of motion known as the law of acceleration

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The second law explains that a greater mass requires a greater force

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7 0
3 years ago
8. Fig. 4.1 shows a heavy ball B of weight W suspended from a fixed beam by two ropes P and Q.
mart [117]

Answer:

The resultant tension of the two ropes is approximately 42.4 N

The length of the line representing the resultant tension is approximately 8.48 cm

Please find included  with the answer the scale drawing created with Microsoft Word

Explanation:

The given parameters are;

The tension in rope P, T_P = 30 N

The tension in rope Q, T_Q = 30 N

The angle the rope, 'P', makes with the horizontal = 45°

The angle the rope, 'Q', makes with the horizontal = 45°

The scale factor of the scale diagram, S.F. = 5.0 N/cm

By the resolution of forces at equilibrium, we have;

The sum of the vertical forces, \Sigma F_y = T_P_y + T_Q_y + W = 0

∴ W = -(T_P_y + T_Q_y)

W = -(30 × sin(45°) + 30 × sin(45°)) = -42.4264068712

The weight of the heavy ball, W ≈ 42.4 N acting downwards

The sum of the horizontal forces, \Sigma F_x = T_P_x + T_Q_x  = 0

The length of the resultant force, W = W/(S.F.) ≈ 42.4 N/(5.0 N/cm) = 8.48 cm

The drawing of the vectors using the scale factor of 5.0 N/cm is created using Microsoft Word is included

3 0
3 years ago
? Which statement is true of an object in equilibrium?
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The answer is C,<span> The sum of all forces acting on the object is zero. hope that helps!!</span>
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