Answer:
Explanation:
Formula for the calculation of no. of Mol is as follows:
Molecular mass of Ag = 107.87 g/mol
Amount of Ag = 5.723 g
Molecular mass of S = 32 g/mol
Amount of S = 0.852 g
Molecular mass of O = 16 g/mol
Amount of O = 1.695 g
In order to get integer value, divide mol by smallest no.
Therefore, divide by 0.02657
Therefore, empirical formula of the compound =
Answer:
Na₂CO₃•H₂O
Explanation:
After it is heated, the remaining mass is the mass of sodium carbonate.
30.2 g Na₂CO₃
Mass is conserved, so the difference is the mass of the water:
35.4 g − 30.2 g = 5.2 g H₂O
Convert masses to moles:
30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃
5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O
Normalize by dividing by the smallest:
0.285 / 0.285 = 1.00 mol Na₂CO₃
0.289 / 0.285 = 1.01 mol H₂O
The ratio is approximately 1:1. So the formula of the hydrate is Na₂CO₃•H₂O.
The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element.
Answer:
0.260 Celsius
Explanation:
q =c x m x (T2-T1)
c - specific heat of water 4.186 J/g.C
T2-T1 = q /(c x m) = 0.959 /(4.186 x 0.88) = 0.959/3.68 =0.260 C
Answer:
chemical and nuclear reaction
Explanation:
