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Lemur [1.5K]
3 years ago
12

PLEASE HELPPP MEEEE

Chemistry
2 answers:
disa [49]3 years ago
5 0

Answer: Option (b) is the correct answer.

Explanation:

Freezing point is defined as the point at which liquid state of a substance changes into solid state.

So, in the given table it is shown that at temperature 18^{o}C the substance is changing into solid state. Whereas at 23^{o}C the substance is in liquid state.

Hence, 18^{o}C will be the freezing point of the substance.

Thus, we can conclude that the statement its freezing point is 18^{o}C, is correct about the unknown substance.

Cloud [144]3 years ago
4 0

The second statment is true and right. Hope this helps!!

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Consider the following reaction where Kc = 1.29×10-2 at 600 K: COCl2 (g) CO (g) + Cl2 (g) A reaction mixture was found to contai
vaieri [72.5K]

Answer:

1. In order to reach equilibrium COCl₂(g) must be consumed.

B. False

2. In order to reach equilibrium Kc must increase.

B. False .

3. In order to reach equilibrium CO must be consumed.

A. True.

4. Qc is greater than Kc.

A. True

5. The reaction is at equilibrium. No further reaction will occur.

B. False.

Explanation:

Based on the reaction:

COCl₂(g) → CO (g) + Cl₂(g)

And Kc is defined as:

Kc = 1.29x10⁻² = [CO] [Cl₂] / [COCl₂]

Molar concentrations of each species are:

[COCl₂] = 0.104 moles of COCl₂ / 1L = 0.104M

[CO] = 4.66×10⁻² moles of CO / 1L = 4.66×10⁻²M

[Cl₂] = 3.76×10⁻² moles of Cl₂ / 1L = 3.76×10⁻²M

Replacing in Kc formula:

4.66×10⁻²M × 3.76×10⁻²M / 0.104M = 1.68x10⁻²

As the concentrations are not in equilibrium, 1.68x10⁻² is defined as the <em>reaction quotient, Qc</em>.

As Qc > Kc, the reaction will shift to the left producing more COCl₂ and consuming CO and Cl₂. Thus

1. In order to reach equilibrium COCl₂(g) must be consumed.

B. False

2. In order to reach equilibrium Kc must increase.

B. False . Kc is a constant that never change.

3. In order to reach equilibrium CO must be consumed.

A. True.

4. Qc is greater than Kc.

A. True

5. The reaction is at equilibrium. No further reaction will occur.

B. False. The reaction is in equilibrium when Qc = Kc

6 0
4 years ago
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netineya [11]

Answer:

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Explanation:

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4 0
3 years ago
Read 2 more answers
Chemistry!! Please help asap!! Will mark brainiliest!!
Whitepunk [10]
<h2>Answer:</h2><h3>Part 1. </h3>

Option B is correct option.

The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing  OH- ions.

Explanation:

Full equation:

                                          2MnO2 + H2O + 2e-  → Mn2O3 + 2OH-

<h3>Part 2:</h3>

The option B which is Mg is stronger reducing agent than Ag is correct option.

Explanation:

Equation:

                               Mg(s) + 2Ag+ (aq) → Mg2+ (aq) + 2Ag(s)

According to equation Mg converts to Mg+2 which means it gives to electron to reduce Ag. So it act as an reducing agent.

<h3>Part 3:</h3>

The correct option is B. Which is  5, 1, 8, 5, 1, 4.

Explanation:

Full equation :

                  5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) --> 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O (l)


<h3 />

5 0
3 years ago
3. Which of the following is the correct mathematical expression to use to
xxTIMURxx [149]

Answer:

The pH of a 0.10 Maqueous Ba(OH)2 solution at 25°C is 13.30

Explanation:

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We will find H+ ion concentration

As we know that

[H+][OH−]=1.0×10−14M

Given -  

[OH−]=2.0×10−1M

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[H+]=5.0×10−14M

pH=−log10[H+]

pH=−log10[5.0×10−14] = 13.30.

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