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1 year ago

What is the value of the expression 9+4n-1 when n = 3?

1 answer:

6 0

Answer: 9+4n-1 = 20

We can solve this by substitution.
Replace n with the value given, 3 (remember 4n means 4 times n):
9 + 4*3 - 1
Then work it out using arithmetic
9+12-1
=20

You might be interested in

Is (x+7) a factor of f(x)= x^3-3x^2+2x-8

nikklg [1K]

Answer:

Step-by-step explanation:

Use synthetic division to answer this. If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.

We use -7 as the divisor in synth. div. This comes from the factor (x + 7):

-7 / 1 3 2 -8

-7 28 -210

-------------------------

1 -4 30 -218

Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.

6 0

3 years ago

Which of the following expressions results in 0 when evaluated at x = 4?

Zarrin [17]

(x-10)(x-4) because 4-10=6 then multiply that by 0 from 4-4

8 0

3 years ago

Shabelly practiced for 4 2/5 hours during week one, then 9 2/3 hours the following week.

IrinaVladis [17]

Answer: 14 1/15

Step-by-step explanation:

4 2/5 + 9 2/3 = 13 + 6/15 + 10/15 = 13 + 16/15 = 14 1/15

7 0

2 years ago

Read 2 more answers

Someone please help ..

sweet [91]

The answer is either c or d hope this helped lol

6 0

3 years ago

Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180

torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

${12}^{2} + {y}^{2} = {13}^{2}$

$144 + {y}^{2} = 169$

$25 = {y}^{2}$

$y = 5$

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

$( - 3) {}^{2} + {x}^{2} = {5}^{2}$