There is a 60 minute gap between the two clocks.
These 60 minutes result of a 1 min advance in one for each hour and a 2 min loss in the other.
if we are going 2 mins back and 1 min in
We have a 3 min gap/hour
then to reach a 1 hour gap we would need to go for 2+1+2+1+2+1+2....(20 hours)
since each 3 represent an hour,
to get 60 min gap>60/3=20 hours
Take clock 1 for example, which read 12:00, in reality the time is (12:00-20 minutes)=11:40
or
Take clock 2 for example, which read 11:00, in reality the time is (11:00+20×2 minutes)=11:40
Now go back 20 hours from that;
11:40-20=00:40-9=15:40
There's ur answer 15:40 :)
Answer:
=(a-b)(a^2+ab+b^2)
= a^3+a^2b+ab+ab^2-ba^2-ab^2-b^3
SIMPLIFY
=a^3+ab-b^3
Answer:
0.18 ; 0.1875 ; No
Step-by-step explanation:
Let:
Person making the order = P
Other person = O
Gift wrapping = w
P(p) = 0.7 ; P(O) = 0.3 ; p(w|O) = 0.60 ; P(w|P) = 0.10
What is the probability that a randomly selected order will be a gift wrapped and sent to a person other than the person making the order?
Using the relation :
P(W|O) = P(WnO) / P(O)
P(WnO) = P(W|O) * P(O)
P(WnO) = 0.60 * 0.3 = 0.18
b. What is the probability that a randomly selected order will be gift wrapped?
P(W) = P(W|O) * P(O) + P(W|P) * P(P)
P(W) = (0.60 * 0.3) + (0.1 * 0.7)
P(W) = 0.18 + 0.07
P(W) = 0.1875
c. Is gift wrapping independent of the destination of the gifts? Justify your response statistically
No.
For independent events the occurrence of A does not impact the occurrence if the other.
Answer:
x should be 1
I think if you substitute it will just be the index 2 that remains , not sure though .You should probably ask your teacher for assistance
