Answer:
Distance between Montpelier and Columbia is 1020
Step-by-step explanation:
51 mi/hr average:
d = 51 t
60 mi/hr average:
d t = 60*(t-3)
Substitute (1) into (2)
51 t = 60*(t-3)
51 t = 60 t + 180
9 t = 180
t = 20
d = 51 t
= 51 (20)
= 1020
let see distance is 1020 lets check
51 t = 60 * (t-3)
51 (20)= 60* (20-3)
1020 = 60*17
1020 = 1020
Answer:
96
Step-by-step explanation:
Answer:

• subtract eqn(b) from eqn(a);

• find x :

1 I am just typing this because it makes me put 20 characters but the answer is 1
Answer:
-9x + 10
Step-by-step explanation: