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3 years ago

Find the distance cd rounded to the nearest tenth. c=(5,6) and D=(2,2)

1 answer:

4 0

Distance between two points = √[( x₂ - x₁)² + (y₂ - y₁)²]

∴ distance between C and D = √[(x of C - x of D)² + (y of C - y of D)²]

= √[( 5 - 2)² + (6 - 2)²]

= √[( 3)² + (4)²]

= √(9 + 16)

∴ distance between C and D = 5 units

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A contractor records the areas, in square feet, of a small sample of houses in a neighborhood to determine data about the neighb

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Option c is the correct answer which represents the numerator in the calculation of variance and standard deviation.

<h3>What are the variance and standard deviation? </h3>

In statistics, variance is a measure of the variation of data from the mean, whereas standard deviation is the measure of the normal distribution of statistical data.

A contractor records the areas, in square feet, of a small sample of houses in a neighborhood to determine data about the neighborhood.

2,400; 1,750; 1,900; 2,500; 2,250; 2,100

we need to find which of the following represents the numerator in the calculation of variance and standard deviation.

(225 $)^{2}$ + (–425 $)^{2}$ + (–275 $)^{2}$ + (325 $)^{2}$ + (75 $)^{2}$ + (–75 $)^{2}$ = 423,750

(650 $)^{2}$ + (–150 $)^{2}$ + (–600 $)^{2}$ + (250 $)^{2}$ + (150 $)^{2}$ + (–300 $)^{2}$ = 980,000

(250 $)^{2}$ + (–400 $)^{2}$ + (–250 $)^{2}$ + (350 $)^{2}$ + (100 $)^{2}$ + (–50 $)^{2}$ = 420,000

92416.60

The variance is 84000

The standard deviation is 290

mean = (2400+1750+1900+2500+2250+2100)/6

mean = 2150

Subtract the data values from the mean to get

2400-2150 = 250

1750-2150 = -400

1900-2150 = -250

2500-2150 = 350

2250-2150 = 100

2100-2150 = -50

The differences are 250, -400, -250, 350, 100, -50

Then you square those values and add up the squares

(250)^2 + (-400)^2 + (-250)^2 + (350)^2 + (100)^2 + (-50)^2 = 420,000

Hence, option c is the correct answer which represents the numerator in the calculation of variance and standard deviation.

Learn more about variance;

brainly.com/question/14116780

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